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lara [203]
3 years ago
12

Rewrite the equation below so that it does not have fractions.

Mathematics
2 answers:
vova2212 [387]3 years ago
7 0
<h2>>> Answer</h2>

_________

\:

\frac{3}{4} x  - 5 =  \frac{3}{8}

\frac{3}{4} x =  \frac{3}{8}  + 5

\frac{3}{4} x = 5 \frac{3}{8}

\frac{3}{4} x =  \frac{43}{8}

x =  \frac{43}{8}  \times  \frac{4}{3}

x =  \frac{172}{24}

x =  \bold{7 \frac{1}{6}}

Eduardwww [97]3 years ago
5 0

Answer:

6x-40=3

Step-by-step explanation:

3/4 x -5 =3/8

Multiply each side by 8 to get rid of the fractions.

8(3/4x -5 ) =8*3/8

Distribute

6x-40=3

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Find the sum.
hichkok12 [17]

Answer:

C - 19/24

Step-by-step explanation:

Take the fractions and put the denominators into a common factor

\frac{1}{3}+ \frac{1}{3}+ \frac{1}{8}

\frac{8}{24}+ \frac{8}{24}+ \frac{3}{24}

Add Numerators Across

\frac{16}{24}+ \frac{3}{24}

\frac{19}{24}

8 0
3 years ago
Could someone help me please thank you
lara31 [8.8K]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
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Leia cuts congruent triangular patches with an area of 45 square centimeters from a rectangular piece of fabric that is 18 centi
zimovet [89]
The number of patches that Leia can cut from 32 pieces of the fabric measuring  18 cm by 10 cm will be as follows:
Number of pieces=[total area of fabric]/[area of patch]
area of fabric=18×10=180 cm²
Area of 32 patches=180×32=5760 cm²

Area of patch=45 cm²

Number of patches=5760/45=128 patches 
6 0
4 years ago
PLS HELP ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITS RIGHT OR WRONG. SHOW PROOF.
VMariaS [17]

Answer:

1:3

Step-by-step explanation:

3 0
3 years ago
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In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
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