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Vika [28.1K]
3 years ago
8

Two less than three-fifths a number less or equal to forty-one

Mathematics
2 answers:
Ivan3 years ago
8 0

Answer:

\frac{3}{5}x-2\leq 41

x\leq \frac{215}{3}

Step-by-step explanation:

In inequality,

'≥' = greater than equal to,

'≤' = less than equal to,

Given phrase,

two less than three-fifths a number less or equal to forty-one,

Let x represents the unknown number,

two less than three-fifths of a x = \frac{3}{5}x-2

\frac{3}{5}x-2 less or equal to forty-one,

\frac{3}{5}x-2\leq 41

Which is the required inequality,

By solving it,

\frac{3}{5}x\leq 43

x\leq \frac{43\times 5}{3}=\frac{215}{3}

Leviafan [203]3 years ago
6 0
(x divided by 3/5) -2<41
                                -
i hope this helps

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A fuel tank contains 1 3/4 gallons of gasoline. Casey adds 33 1/3 gallons of
romanna [79]

Answer:

The gallons of gas the tank contain now is <u>35 1/12</u>.

Step-by-step explanation:

Given:

Fuel tank contains 1 3/4 gallons of gasoline.

Casey adds 33 1/3 gallons of  gasoline to the tank.

Now, to find the total gallons of gas the tank contain.

Converting the mixed fractions into improper.

Gallons of gasoline in fuel tank =1\frac{3}{4}=\frac{7}{4}.

Gallons of gasoline Casey adds =33\frac{1}{3} =\frac{100}{3}.

<u>According to question:</u>

By adding we get the total gallons of gasoline now tank contain:

\frac{7}{4} +\frac{100}{3}

=\frac{7\times 3+100\times 4}{12}

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=\frac{421}{12}

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5 0
3 years ago
I’m trying to correct this problem but I don’t know how can someone help me
BartSMP [9]

Remark

It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.

Method

You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.

Distance from the Park to the city center.

a = 3   [distance east]

b = 4  [distance south]

c = ??

c^2 = 3^2 + 4^2        Take the square root of both sides.

c = sqrt(3^2 + 4^2)

c = sqrt(9 + 16)          Add

c = sqrt(25)

c = 5

So the distance from the park to the city center is 5 miles

Distance from City center to the mall

a = 2 miles [distance east]

b = 2 miles [distance north]

c = ??

c^2 = a^2 + b^2   Substitute

c^2 = 2^2 + 2^2   Expand this.

c^2 = 4 + 4

c^2 = 8             Take the square root of both sides.

sqrt(c^2) = sqrt(8)

c = sqrt(8)          This is the result

c = 2.8

Answer

Total distance = 5 + 2.8 = 7.8

6 0
3 years ago
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