The last option:
Avoid forwarding e-mail messages unless you have permission to do so.
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.
Answer:
Binary information must be encoded in some way before transmission over the Internet. ... Copper wire is used to transmit binary messages using electricity - a voltage on the wire means one state, and no voltage means the other. Fiber-optic cables, on the other hand, use light (on or off) to transmit a binary message.
Common input devices include the keyboard, image scanner, and integrated video cameras. These also include the microphone, mouse, joystick controller, gamepad or joypad, webcam, digital pen, and others. Input devices are computer hardware used to control signals and provide data to a computer or an information appliance.
In general, synchronous communication means you have to wait for the answer all the time. The programming logic is simpler, but the cost that you spend a lot of time waiting.
If the options are:
<span>a. The people communicating don't need to be online at the same time.
b. There is lag time in the communication.
c. The communication occurs in real time.
a is false, you do need to be online to receive the message
b is true, typically you continue only after an acknowledgement
c is true, you wait for acknowledgement that occurs in real time (not necessarily fast though)</span>
