Answer and Explanation:
Given data:
Distance (D) = 40 KM
Speed of light in the fiber =Distance/ speed of light in the fiber
a) Delay (P) = Distance/ speed of light in the fiber
= (40,000 Meters/2×108 m/s)
=( 40×103 Meters/2×108 m/s)
Propagation delay (P) = 0.0002 seconds or 200 microseconds
b)
if propagation delay is 0.0002 Seconds roundup trip time (RTT) will be 0.0004 Seconds or 400 micro Seconds
Essentially since transmission times and returning ACKs are insignificant all we really need is a value slightly greater than 0.0004 seconds for our timeout value.
c)
The obvious reasons would be if the data frame was lost, or if the ACK was lost. Other possibilities include extremely slow processing on the receive side (late ACK).
Or Extremely Slow Processing of the ACK after it is received back at the send side.
Answer:
My guess would be C2-C11, But I may be wrong
Imagine a graph
Hope this helps....
Answer:
- ADSL.
- Ethernet Home Networks.
- Fiber Optics.
- Cable Television.
Explanation:
In Computer, Guided media also known as bounded media involves the use of cable such as fibre-optic cables, coaxial cable to transmit data signals from one system device to another.
Examples of systems using guided media are;
- ADSL.
- Ethernet Home Networks.
- Fiber Optics.
- Cable Television.
Answer:
The main objects of a head frame, or poppet head, are to support the winding pulley firmly and to guide the cage above the surface to the discharging stage.