Answer:
The equation of the line that is perpendicular to the line that passes through the point (-4, 2) is y = -9·x/5 + 18
Step-by-step explanation:
The coordinates of the point of intersection of the two lines = (5, 9)
The coordinates of a point on one of the two lines, line 1 = (-4, 4)
The slope of a line perpendicular to another line with slope, m = -1/m
Therefore, we have;
The slope, m₁, of the line 1 with the known point = (9 - 4)/(5 - (-4)) = 5/9
Therefore, the slope, m₂, of the line 2 perpendicular to the line that passes through the point (-4, 4) = -9/5
The equation of the line 2 is given as follows;
y - 9 = -9/5×(x - 5)
y - 9 = -9·x/5 + 9
y = -9·x/5 + 9 + 9
y = -9·x/5 + 18
Therefore, the equation of the line that is perpendicular to the line that passes through the point (-4, 2) is y = -9·x/5 + 18.
14 - 2x = 4a - 16
First, add 2a to both sides. / Your problem should look like:
Second, simplify 4a - 16 + 2a to get 6a - 16. / Your problem should look like:
Third, add 16 to both sides. / Your problem should look like:
Fourth, add 14 + 16 to get 30. / Your problem should look like:
Fifth, divide both sides by 6. / Your problem should look like:
Sixth, 6 goes into 5 to get 30, so simplify

to 5. / Your problem should look like:
Seventh, switch your sides. / Your problem should look like:

Answer:
a = 5
When dividing these, the powers are subtracted form each other.
We could split up the fraction into r's, s's, and t's.
r^-3 / r^2 = r^-5 [think of it as -3 -2]
s^5 / s = s^4
t^2 / t^-2 = t^4 [2 - - 2 = 4]
A negative power places it on the bottom of the fraction and the minus sign is removed from the power.
So the answer is A: (s^4)(t^4)/r^5
Find the cosine ratio of angle ΘΘ. Hint: Use the slash symbol ( / ) to represent the fraction bar and enter the fraction with no spaces. (4 points)
Cosine=adjacent/hypotenuse
adjacent=8
Hypotenuse =17
cosΘ=8/17
114.50 if you add everything together and then subtract 67.50 you’ll get your answer