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SOVA2 [1]
3 years ago
12

a shipping company makes a display to show how many cubes can fit into a large box. each cube has a side of 2 inches. the large

box has sides of 10 inches. use exponents to express the volume of each cube and the large boxvolume of cubes _____ volume of large box_____find how many cube will fit in the boxsuppose the shipping company were packing balls with a diameter of 2 inches instead of cubes. would the large box hold more balls or fewer balls than the cubes? explain your answersuppose the size of each cube is doubles and the size of the large box is doubled. how many of these new cubes will fit in the new large box? explain how you found your answer.
Mathematics
1 answer:
ehidna [41]3 years ago
4 0

1 The volume of the cube is 2 * 2 * 2 or 2 ^ 3 in ^ 3 while the volume of the large box is 10 * 10 * 10 or 10 ^ 3 in ^ 3.

2 The answer is 125. Just divide the large box to the volume of the cube 1000 / 8 = 125.

3 The box will hold the same number of balls as small boxes. With the balls, there is empty space.

4 The answer is still 125. Just find the volume of the box and of the cube. Divide the box volume by the cube volume.

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A table is on sale for $481, which is 26% less than the regular price.
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4 years ago
A restaurant chain is measuring the levels of arsenic in chicken from its suppliers. The question is whether there is evidence t
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Answer:

The p-value of the test is 0.1515.

Step-by-step explanation:

The hypothesis for the test can be defined as follows:

<em>H</em>₀: The mean level of arsenic is 80 ppb, i.e. <em>μ</em> = 80.

<em>Hₐ</em>: The mean level of arsenic is greater than 80 ppb, i.e. <em>μ</em> > 80.

As the population standard deviation is not known we will use a t-test for single mean.

It is provided that the sample mean was, \bar X=91.

The adjusted sample provided is:

S = {57, 64, 70, 82, 84, 123}

Compute the sample standard deviation as follows:

\bar x=\farc{57+64+70+82+84+123}{6}=80\\\\s=\sqrt{\frac{1}{6-1}\times [(57-80)^{2}+(64-80)^{2}+(70-80)^{2}+...+(123-80)^{2}]}=23.47

Compute the test statistic value as follows:

 t=\frac{\bar X-\mu}{\s/\sqrt{n}}=\frac{91-80}{23.47/\sqrt{6}}=1.148

Thus, the test statistic value is 1.148.

Compute the p-value of the test as follows:

 p-\text{value}=P(t_{n-1}

                =P(t_{6-1}

*Use a t-table.

Thus, the p-value of the test is 0.1515.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

p-value = 0.1515 > α = 0.05

The null hypothesis will not be rejected at 5% level of significance.

Thus, concluding that the mean level of arsenic in chicken from the suppliers is 80 ppb.

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4 years ago
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