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3 years ago

How do I solve these and what is the answer?

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

5 0

I don't know how to solve this without knowing the a, b, n, and x values, unless you are just telling us to simplify it

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Write the fraction 2/5 as an equivalent with the given denominator 25

OlgaM077 [116]

Answer:

10/25

Step-by-step explanation:

2/5 = x/25

We need to multiply the bottom by 5 to get to 25

5*5 = 25

What we to the bottom, we do the the top

2/5 * 5/5 = 10/25

6 0

3 years ago

Read 2 more answers

16) A company has found that its expenditure rate per day (in hundreds of dollars) on a certain type of job is given by E'(x) =

erastova [34]

Answer:

$61

Step-by-step explanation:

Given

Number of days, x = 5

Expenditure per day, E'(x) = 10x + 11

Required

Determine the expenditure per day (E'(x))

From the question, we have that

$E'(x) = 10x + 11$

Substitute 5 for x

$E'(5) = 10 * 5 + 11$

$E'(5) = 50 + 11$

$E'(5) = 61$

Hence, the expenditure for 5 days is $61

3 0

3 years ago

A commuter must pass through 5 traffic lights on her way to work and will have to stop at each one that is red. She estimates th

sergij07 [2.7K]

Answer:

(a) The mean or expected value of X is 2.2.

(b) The standard deviation of X is 1.3.

Step-by-step explanation:

Let X = number of times the traffic light is red when a commuter passes through the traffic lights.

The probability distribution of X id provided.

The formula to compute the mean or expected value of X is:

$\mu=E(X)=\sum x.P(X=x)$

The formula to compute the standard deviation of X is:

$\sigma=\sqrt{E(X^{2})-(E(X))^{2}}$

The formula of E (X²) is:

$E(X^{2})=\sum x^{2}.P(X=x)$

(a)

Compute the expected value of X as follows:

$E(X)=\sum x.P(X=x)\\=(0\times0.06)+(1\times0.25)+(2\times0.35)+(3\times0.15)+(4\times0.13)+(5\times0.06)\\=2.22\\\approx2.2$

Thus, the mean or expected value of X is 2.2.

(b)

Compute the value of E (X²) as follows:

$E(X^{2})=\sum x^{2}.P(X=x)\\=(0^{2}\times0.06)+(1^{2}\times0.25)+(2^{2}\times0.35)+(3^{2}\times0.15)+(4^{2}\times0.13)+(5^{2}\times0.06)\\=6.58$

Compute the standard deviation of X as follows:

$\sigma=\sqrt{E(X^{2})-(E(X))^{2}}\\=\sqrt{6.58-(2.22)^{2}}\\=\sqrt{1.6516}\\=1.285\\\approx1.3$

Thus, the standard deviation of X is 1.3.

4 0

4 years ago

Read 2 more answers

Describe the graph of y={1/(2x-10)}-3 compared to the graph of y=1/x

tester [92]

$\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)= A( Bx+ C)+ D
\\\\
~~~~y= A( Bx+ C)+ D
\\\\
f(x)= A\sqrt{ Bx+ C}+ D
\\\\
f(x)= A(\mathbb{R})^{ Bx+ C}+ D
\\\\
f(x)= A sin\left( B x+ C \right)+ D
\\\\
--------------------$

$\bf \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\
\bullet \textit{ flips it upside-down if } A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if } B\textit{ is negative}$

$\bf ~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{ C}{ B}\\
~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by } D\\
~~~~~~if\ D\textit{ is negative, downwards}\\\\
~~~~~~if\ D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{ B}$

with that template in mind, let's check these two

$\bf \stackrel{parent}{y=\cfrac{1}{x}}\qquad \qquad\qquad \qquad \stackrel{transformed}{y=\cfrac{1}{\stackrel{B}{2}x\stackrel{C}{-10}}\stackrel{D}{-3}}\\\\
-------------------------------\\\\
B=2\qquad \textit{shrinks horizontally by }\frac{1}{2}
\\\\\\
C=-10\qquad \cfrac{C}{B}=\cfrac{-10}{2}\implies -5\qquad \textit{horizontally right-shifted by }5
\\\\\\
D=-3\qquad \textit{vertically down-shifted by }3$

7 0

3 years ago

On your last math quiz, you got 15

dlinn [17]

Answer: 75%

Step-by-step explanation: So 15/20 simplified is 3/4 and 3 divided by 4 equals 0.75. To convert a decimal to a percentage, you multiply 0.75 by 100 to get 75%.

3 0

3 years ago