3 years ago

20points+brainliest to whoever answers this

Mathematics

2 answers:

natta225 [31]3 years ago

7 0

Answer:

Preciate you

Step-by-step explanation:

Bond [772]3 years ago

7 0

Hindjdjdjdjdhdhdhbdbdbdbbdbdbd

You might be interested in

Find an angle such that is 4 times its complement equals 200°

allochka39001 [22]

Answer:

40 degrees

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Noam must share a cash prize equally among 4 winners. If each person receives $125, what is the amount of the prize

sertanlavr [38]

Answer:

c. 500

Step-by-step explanation:

125+125=250

250+125=375

375+125=500

5 0

3 years ago

Read 2 more answers

I need to know how to get the roots for example what is the root of 2 root 5

Harrizon [31]

Answer:

Square roots are when you multiply the same number by itself like for example, the square root of 5 is 25, because 5*5=25

Step-by-step explanation:

5 0

2 years ago

Multiply. Check picture.

VashaNatasha [74]

The answer is $3x^4-13x^3-x^2-11x+6$ .

Solution:

Use algebraic identity: $a^m\times a^n=a^{m+n}$

For example: $x^2\times x=x^{2+1}=x^3$

Given expression $(x^2-5x+2)$ and $(3x^2+2x+3)$ .

To multiply these equations.

$(x^2-5x+2)\times(3x^2+2x+3)$

$=x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)$

$=(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)$

$=3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6$

Combine like terms together.

$=3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6$

$=3x^4-13x^3-x^2-11x+6$

$(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6$

Hence the answer is $3x^4-13x^3-x^2-11x+6$ .

3 0

3 years ago

Hello there

den301095 [7]

Answer:

4: 20 cm3

Step-by-step explanation:

6 x 4 = 24

24 x 10 = 240

it is cubic since it is volume

7 0

3 years ago

Read 2 more answers