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lawyer [7]
3 years ago
15

Camp oaks get 32 boxes of orange juice and 56 bags of Apple juice is shelf in the cup board can hold eight boxes of juice what i

s the least number of cells need it for all of the Juice boxes
Mathematics
1 answer:
geniusboy [140]3 years ago
6 0
The answer is 4 cells
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3 years ago
A baseball is thrown in a parabolic arc. It's position above the ground at a given point in time can be represented by the quadr
SCORPION-xisa [38]

Answer:

The baseball reached 9 feet high above the ground

Step-by-step explanation:

The given quadratic function representing the position of the baseball above ground is p(t) = 1/2·g·t² + v₀·t + p₀

Where;

t ≥ 0

g = -32 ft./sec²

v₀ = The initial velocity

p₀ = The initial position

Given that when the ball is thrown, we have;

The initial, straight up, velocity, v₀ = 16 ft./sec

The initial position, p₀ = 5 ft.

Substituting the above values in the quadratic function representing the position of the baseball above ground, we have;

p(t) = 1/2·(-32)·t² + 16·t + 5 = 16·t - 16·t² + 5

At the maximum point, the rate of change of the height with time = 0, therefore;

dp(t)/dt = 0 = d(16·t - 16·t² + 5)/dt = 16 - 32·t

16 - 32·t = 0

16 = 32·t

t = 16/32 = 0.5 seconds

Therefore, the time takes to reach the maximum height = 0.5 seconds

The height (maximum) reached in 0.5 seconds is given as follows;

h(t) = 16·t - 16·t² + 5, from which we have;

h(0.5) = 16 × 0.5 - 16 × (0.5)² + 5 = 9

Therefore, the height baseball reached = 9 ft. above ground

7 0
3 years ago
45 POINTS WILL GIVE BRAINLIEST PLS HELPPPPPPPP
OLEGan [10]
A for both of them add all the numbers up and divide by the amount of numbers to get your iQR but A is right for both
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481*481= 231361

That in expanded form is

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3 years ago
PLZ HELP DONT UNDERSTAND!!!
victus00 [196]
\bf \textit{area of a triangle}=A=\cfrac{1}{2}bh\qquad 
\begin{cases}
b=base\\
h=\textit{height or altitude}
\end{cases}\\\\
-----------------------------\\\\
\textit{area of a trapezoid}\\\\
A=\cfrac{h}{2}(a+b)\qquad 
\begin{cases}
a=\textit{base, or one of the parallel sides}\\
b=\textit{base, or the other parallel side}\\
h=\textit{height, the distance between both}\\
\qquad \textit{parallel sides}
\end{cases}
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3 years ago
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