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Monica [59]
3 years ago
15

a field in the shape of a trapezoid has an area of 13,687.5 square yards .the length of one base is 150yards, and the lenght of

the other base is 215 yards. what is the height?
Mathematics
1 answer:
Leviafan [203]3 years ago
6 0
A=\frac{1}{2}(b_1+b_2)h=13687.5\\\frac{1}{2}((150)+(215))h=13687.5\\(365)h=27375\\h=75

h = 75 yards.
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Pls help me with this
alexgriva [62]

Answer:

x = 1.5

Step-by-step explanation:

Given

\frac{x}{2} \geq 0.75

\frac{x}{2} < 2.5

Required

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if \frac{x}{2} \geq 0.75, then

0.75 \leq \frac{x}{2}

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2 * 0.75 \leq \frac{x}{2} * 2

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2 * \frac{x}{2} < 2.5 * 2

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4 0
3 years ago
Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

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Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

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-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

r = 0.05776

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

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0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

t = 24

It would take 24 minutes for the element to decay to 50 grams

6 0
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