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3 years ago

How can you 24 with the numbers 6,6,2,1

Mathematics

1 answer:

Andreas93 [3]3 years ago

5 0

Add 6 + 6 = 12

Multiple 12 * 2 = 24

Multiple 24 * 1 = 24

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Mrs. Jacobson wants to order toy instruments to give as prizes to her music students. The table shows the prices for various ord

Leona [35]

First let as solve all unit pirce
whistles 21.25 / 25 = $ 0.85 per unit
36 / 50 = $ 0.72 per unit
60 / 80 = $ 0.75 per unit
kazoos
10 / 25 = $ 0.4 per unit
18.50 / 50 = $ 0.37 per unit
27.20 / 80 = $ 0.34 per unit
a.) $ 0.85 - $ 0.72 = $ 0.13
b.) 10 / 25 = $ 0.4 per unit
c.) he must order 80 kazoos she should
order

7 0

2 years ago

Read 2 more answers

Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

3 years ago

5• (4 • x ) simplified

Olegator [25]

Step-by-step explanation:

= 5 • ( 4• x )

= 5 ( 4x )

= 20x

$...$

8 0

2 years ago

Can someone help me with this question if two figures are similar but not congruent, how are they alike, and how are they differ

kenny6666 [7]

Two figures are similar if they have the same shape but not necessarily the same size although they are the same shape they are different sizes

3 0

3 years ago

I don't have any idea.

kaheart [24]

Answer:

Domain = ( -∞,∞), {x|x ∈ R}

Range (-∞,2], {y|y ≤ 2}

Vertex (h,k) = (6,2)

Step-by-step explanation:

(Domain / Range) The absolute value expression has a V shape. The range of a negative absolute value expression starts at its vertex and extends to negative infinity.

(Vertex) To find the x coordinate of the vertex, set the inside of the absolute value

x − 6 equal to 0 . In this case, x − 6 = 0 .

x−6=0

Add 6 to both sides of the equation.

x=6

Replace the variable x with 6 in the expression.

y=−1/3⋅|(6)−6|+2

Simplify−1/3⋅|(6)−6|+2.

y=2

The absolute value vertex is ( 6 , 2 ) .

(6,2)

Hope this helps

6 0

3 years ago