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2 years ago

Find the equation of the line that passes through (3,1) and is parallel to y=2x+1.

Mathematics

1 answer:

creativ13 [48]2 years ago

7 0

9514 1404 393

Answer:

y = 2x -5

Step-by-step explanation:

The parallel line will differ only in the value of c. That can be found using the given point.

y = mx +c

c = y -mx . . . . . . subtract mx to solve for c

c = 1 -2·3 = -5 . . . . . . the value of m is 2 in the given equation (x, y) = (3, 1)

The equation of the parallel line is ...

y = 2x -5

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Mr. endres wants to put fencing around his rectangular shaped backyard. the width of the backyard is 42 feet and the length is t

Anna71 [15]

The the number of feet needed for the fence of the rectangular garden = its perimeter = 252 ft.

<h3>What is the Perimeter of a Rectangle?</h3>

Perimeter = 2(length + width).

The number of feet needed for the fence around the rectangular garden = perimeter of teh rectangular garden.

Given the following:

Width = 42 ft.
Length = 2(42) = 84 ft.

Plug the values into Perimeter = 2(length + width):

Perimeter of the rectangular garden = 2(42 + 84)

Perimeter of the rectangular garden = 252 ft

Therefore, the the number of feet needed for the fence of the rectangular garden = its perimeter = 252 ft.

Learn more about perimeter of rectangle on:

brainly.com/question/24571594

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1 year ago

4x-8y=-26 9x+4y=13 <br> Stuck on my math homework again

Svetllana [295]

Answer:

x = 0, y = 13/4

Step-by-step explanation:

I used elimination to solve the system of equations, but it might be easier to use substitution.

Anyway, hope this helps.

6 0

2 years ago

Use logarithmic differentiation to find the derivative of the function. y = x2cos x Part 1 of 4 Using properties of logarithms,

Arisa [49]

ANSWER

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

EXPLANATION

The given function is

$y = {x}^{2} \cos(x)$

We take natural log of both sides;

$ln(y) = ln({x}^{2} \cos(x) )$

Recall and use the product rule of logarithms.

$ln(AB) = ln(A ) + ln(B)$

This implies that:

$ln(y) = ln({x}^{2} ) + ln( \cos(x) )$

$ln(y) = 2 ln({x} ) + ln( \cos(x) )$

We now differentiate implicitly to obtain;

$\frac{ {y}^{'} }{y} = \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) }$

Multiply through by y,

${y}^{'} = y( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) })$

Substitute y=x²cosx to obtain;

${y}^{'} = {x}^{2} \cos(x) ( \frac{2}{x} - \frac{ \sin(x) }{ \cos(x) ) } )$

Expand:

${y}^{'} = 2x \cos(x) - {x}^{2} \sin(x)$

7 0

2 years ago

Ramal filled 3 pages in a stamp album. This is one sixth of the pages in the album. How many pages are three in Ramal's stamp al

kumpel [21]

Let the total be x
1/6x=3
x/6=3
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therefore Ramal's stamp has 18 pages

6 0

2 years ago

.Shaun estimated that the attendance at a college

Serggg [28]

Answer:

38.72%

Step-by-step explanation:

Estimated attendance = 1,000

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We need to find the percent error of Shaun's estimate. Using the formula as follows :

$\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100$

Put all the values,

$\%=\dfrac{1632-1000}{1632}\times 100\\\\=38.72\%$

So, the percent error of Shaun's estimate is 38.72%.

8 0

2 years ago