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vfiekz [6]
3 years ago
8

Find the equation of the line that passes through (3,1) and is parallel to y=2x+1.

Mathematics
1 answer:
creativ13 [48]3 years ago
7 0

9514 1404 393

Answer:

  y = 2x -5

Step-by-step explanation:

The parallel line will differ only in the value of c. That can be found using the given point.

  y = mx +c

  c = y -mx . . . . . . subtract mx to solve for c

  c = 1 -2·3 = -5 . . . . . . the value of m is 2 in the given equation (x, y) = (3, 1)

The equation of the parallel line is ...

  y = 2x -5

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What is the distance between the set of points (5,9) and (-7,-7)
kiruha [24]

Answer:

The answer is

<h2>20 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3>d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(5,9) and (-7,-7)

The distance between them is

<h3>d =  \sqrt{ ({5 + 7})^{2} + ( {9 + 7})^{2}  }  \\  =  \sqrt{ {12}^{2} +  {16}^{2}  }  \\  =  \sqrt{144 + 256}  \\  =  \sqrt{400}</h3>

We have the final answer as

<h3>20 units</h3>

Hope this helps you

3 0
3 years ago
I really need help with this question
Shtirlitz [24]

Answer:

22

Step-by-step explanation:

Refer to the attachment.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>

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