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vfiekz [6]
2 years ago
8

Find the equation of the line that passes through (3,1) and is parallel to y=2x+1.

Mathematics
1 answer:
creativ13 [48]2 years ago
7 0

9514 1404 393

Answer:

  y = 2x -5

Step-by-step explanation:

The parallel line will differ only in the value of c. That can be found using the given point.

  y = mx +c

  c = y -mx . . . . . . subtract mx to solve for c

  c = 1 -2·3 = -5 . . . . . . the value of m is 2 in the given equation (x, y) = (3, 1)

The equation of the parallel line is ...

  y = 2x -5

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Find the coordinates of point X that lies along the directed line segment from Y(-8, 8) to T(-15, -13) and partitions the segmen
Nataly_w [17]

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x=\frac{m}{m+n} (x_2-x_1)+x_1\\\\y=\frac{m}{m+n} (y_2-y_1)+y_1

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

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Therefore the coordinates of point X is at (-13, -7)

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