Find the equation of the line that passes through (3,1) and is parallel to y=2x+1.
1 answer:
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Answer:
y = 2x -5
Step-by-step explanation:
The parallel line will differ only in the value of c. That can be found using the given point.
y = mx +c
c = y -mx . . . . . . subtract mx to solve for c
c = 1 -2·3 = -5 . . . . . . the value of m is 2 in the given equation (x, y) = (3, 1)
The equation of the parallel line is ...
y = 2x -5
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Answer:
Step-by-step explanation:
yes, since that are 2 points:
y-int is (0, y)
x-int is (x, 0)
since you need only two points for a function with no restrictions, we can use y and x intercepts as points
<span>b is the independent variable ok</span>
Step by step, meaning explaining the equation right and answer?
6 x 11= 66
67 - 66 = 1
67/6 = 11
remainder= 1
Is that considered two equations?
