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3 years ago

8

Johnny left home and drove west 6 miles to Bakersfield for flowers. Then he drove 8 miles north to his girlfriend’s house. How f

ar apart are Johnny’s girlfriends house and Johnny’s house?

1 answer:

geniusboy [140]3 years ago

8 0

They live 2 miles apart

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F(x)=3x^3-12x^2+9x what the factor<br>

alexandr1967 [171]

Answer:

f(x) = 3x(x-1)(x-3)

Step-by-step explanation:

f(x) = 3x³-12x²+9x = 3x(x²-4x+3) =

= 3x(x²-x-3x+3) = 3x[x(x-1)-3(x-1)] =

= 3x[(x-1)(x-3)] = 3x(x-1)(x-3)

6 0

3 years ago

Read 2 more answers

A boat on a river travels downstream between two points, 90 mi apart, in 1 h. The return trip against the current takes 2 1 2 h.

docker41 [41]

Answer:

A)63miles per hour.

B)27 miles per hour

Step-by-step explanation:

HERE IS THE COMPLETE QUESTION

boat on a river travels downstream between two points, 90 mi apart, in 1 h. The return trip against the current takes 2 1 2 h. What is the boat's speed (in still water)??b) How fast does the current in the river flow?

Let the speed of boat in still water = V(boat)

speed of current=V(current)

To calculate speed of boat downstream, we add speed of boat in still water and speed of current. This can be expressed as

[V(boat) +V(current)]

It was stated that it takes 1hour for the

boat to travels between two points of 90 mi apart downstream.

To calculate speed of boat against current, we will substact speed of current from speed of boat in still water. This can be expressed as

[V(boat) - V(current)]

and it was stated that it takes 2 1/2 for return trip against the Current

But we know but Speed= distance/time

Then if we input the stated values we have

V(boat) + V(current)]= 90/1 ---------eqn(1)

V(boat) - V(current) = 90/2.5----------eqn(2)

Adding the equations we have

V(boat) + V(current) + [V(boat) - V(current)]= 90/2.5 + 90/1

V(boat) + V(current) + V(boat) - V(current)]=90+36

2V(boat)= 126

V(boat)=63miles per hour.

Hence, Therefore, the speed of boat in still water is 63 miles per hour.

?b) How fast does the current in the river flow?

the speed of the current in the river, we can be calculated if we input V(boat)=63miles per hour. Into eqn(1)

V(boat) + V(current)]= 90/1

63+V(current)=90

V(current)= 27 miles per hour

Hence,Therefore, the speed of current is 27 miles per hour.

7 0

2 years ago

5x−4≥12 OR 12x+5≤−4 please answer asap and right and explain like im 5 how to solve OR problems ill give brainliest and a lot of

weeeeeb [17]

Answer: x>_3.2 OR x<_ -0.75

Step-by-step explanation: first break down your compound inequality. 5x-4>_12

You first cancel out your constants by adding 4 to both sides. Now you’re left with 5x>_16 then to cancel five you have to divide on both sides by five which equals to 3.2. Then, x>_ 3.2.

Next you do your second part, 12x+5<_-4

So first cancel out the constant of 5 by subtracting 5 on both sides, making the equation 12x<_-9. Now, you divide by 12 on both sides, making it -9/12. Which effectively is -0.75. Therefor, the answer being x<_ -0.75. Add the two together x>_3.2 OR x<_0.75

4 0

3 years ago

I need it now please help

gulaghasi [49]

B. A smaller percentage of second-lunch students (38%) eat outside.

5 0

3 years ago

SOLVE USING ELIMINATION *20 POINTS*

V125BC [204]

1. No answer ( may be due to incorrect question)

2. x = -3

y = 4

3. x= 4

y = 2

4.x = -63/40

y= -19/20

Step 1

Multiply equation 1 by the coefficient of x in equation 2

Multiply equation 2 by the coefficient of x I'm equation 1

(after completing this step you will derive equation 3 and 4 )

Step 2

Subtract equation 4 from equation 3

Step 3

Divide both sides of the equation by the coefficient of y

Step 4

substitute your value for y in equation 1 or 2

(after this you will derive the values of x)

Note : This method is for the Elimination of x

I hope it helps

5 0

3 years ago