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irina1246 [14]
3 years ago
7

In referring to snipers what is 2 minutes left mean

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0
<span>The sniper is talking about the minute of angle. One minute of angle is 1/60th of one degree. It is 1.047 at 100 yards, so it is about 1 at that measurement. At 2 minutes of angle, it is about 2 at 200 yards.</span>
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How to simplify please help
Luda [366]

Okay, the image is a little tough to see, but I believe it looks something like this:

(5² -10 / 17 - 3 * 4) -1

The first step [remember PEMDAS] is parentheses

Next comes Exponents:

(25 - 10 / 17 - 3 * 4) -1

Then Multiplication:

(25 - 10 / 17 - 12) - 1

Then Division [which we can't do yet since it isn't fully simplified], so we skip to Addition... nothing again, then subtraction.

(15 / 5) - 1

Then we can divide:

(3) - 1

Then subtract!

2

The answer to your problem is 2.

Hope that helps!

4 0
4 years ago
I have 0 idea. can someone help me?
aliina [53]

Answer:

2a+8 (square root b)................. third option

6 0
2 years ago
I need help plz plz plz
Katena32 [7]
Your answer to this question is B
3 0
3 years ago
Answer the question in the picture pls WORTH 50 POINTS PLUS BRAINLIEST FOR FIRST CORRECT ANSWER
Alexus [3.1K]

Answer:

A

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−y+4≥8

Step 2: Subtract 4 from both sides.

−y+4−4≥8−4

−y≥4

Step 3: Divide both sides by -1.

−y

−1

≥

4

−1

y≤−4

5 0
3 years ago
Read 2 more answers
Distributions and Comparing Data Project
LenKa [72]

Answer:

1. The shape of the histogram created with MS Excel is approximately bell shaped and approximately evenly spread about the central (largest counts) values

The shape of the box plot created with MS Excel is approximately evenly distributed

2. The appropriate measure of central tendency for a bell shaped histogram is the mean and median, due to the approximately equal distribution about the highest frequency class

3. Part A

The 15 numbers between 1  and 20 generated by a random generator are;

1, 8, 8, 15, 4, 18, 11, 6, 17, 1, 18, 15, 10, 12, 11

The measure of center is the mean =  (1+8+8+15+4+18+11+6+17+1+18+15+10+12+11)/15 = 155/15 = 31/3

The measure of spread used is the variance, s² = 32.38

Where, \,s^2 =\dfrac{\sum \left (x_i-\bar x  \right )^{2} }{n - 1}

{\sum \left (x_i-\bar x  \right )^{2} } = 453.333

n = 15

s² = 453.\overline 3/(15 - 1) = 32.38

Part B

The measure of central tendency are the mean and the median because the size of the data (n = 15), is 75% of the population (N = 20) nd therefore the data is approximately normal and can be represented by the mean and the standard deviation

Step-by-step explanation:

4 0
3 years ago
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