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Aneli [31]
2 years ago
7

How many quarts of pure antifreeze must be added to 5 quarts of a 10 ​% antifreeze solution to obtain a 20 ​% antifreeze​ soluti

on?
Mathematics
1 answer:
Black_prince [1.1K]2 years ago
4 0
Hey let’s be friends
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Help me please please
artcher [175]

Answer:

L = 34 - 0.5d

21 feet

Step-by-step explanation:

The initial water level ; 34

the amount is rises per day; 0.5

"L" is the water level,

"d" is the days passed.

In order to find the water level, one will have to multiply the amount the water rises each day, by the days passed. Then one will have to subtract that from the initial water level, hence the equation formed is the following;

L = 34 - 0.5d

Substitute in 26 for "d", to solve for the water level after 26 days.

L = 34 - 0.5(26)

L = 34 - 13

L = 21

4 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
2 years ago
This graph shows the cost of a small cheese pizza at 3 different restaurants. a) explain how the size of the bars gives a false
nlexa [21]

I would answer, but I don’t see the graph. If you add the graph I could help (if you want of course, not trying to be rude. Sorry!)

8 0
3 years ago
1. A 2012 survey conducted by the local paper in Columbus, Ohio one week before Election Day
mash [69]

Answer:

The description again for the problem is listed throughout the section below on explanations.

Step-by-step explanation:

A 2012 survey conducted a week since Voting day because the local paper in Columbus asked voters whatever individual they might vote for the state attorney. 37% of respondents said that they'd vote for both the dem candidate. In reality, 41 percent voted for both the Democratic nominee on Elections Day.

The 37% is supported by a survey as well as being a factual estimate. The sample proportion is denoted by "P". Therefore,

⇒  P = 0.37

The specific proportion becomes supplied as a factor of 41% = 0.41. Since the importance of proportion is real.  The proportion of community is represented as p or π

Hence p = 0.41.

4 0
2 years ago
Can anyone please help with this problem ASAP ?
lara31 [8.8K]

Answer:

4 would be $55.00 and 8 would be $75.00

8 0
2 years ago
Read 2 more answers
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