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2 years ago

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How many quarts of pure antifreeze must be added to 5 quarts of a 10 % antifreeze solution to obtain a 20 % antifreeze soluti

on?

1 answer:

Black_prince [1.1K]2 years ago

4 0

Hey let’s be friends

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evaluate the impact of risky behaviour on your personal expectations in relation to your career help with maths too

timofeeve [1]

Step-by-step explanation:

In triangle ADE:

sum of all angles is 180.

3x-10+58+42=180

3x+90=180

3x=180-90

3x=90

x=90/3

x=30

As line DA and CB are parallel:

angle D=angle C

angle y=58

In angle BCE, sum of angles is 180.

z+58+42=180

z+100=180

z=180-100

z=80

4 0

2 years ago

The difference of two numbers is 8. If the sum of the smaller number and the square of the larger

galben [10]

Answer:

12

Step-by-step explanation:

12^2 is the greatest number that is closest to 148. then there is 4 as the smaller number 12-4=8

144+4=148

6 0

2 years ago

A pool measuring 8 meters by 28 meters is surrounded by a path of uniform width, as shown in the figure. If the area of the poo

Greeley [361]

28 because the wiishddbehehhe is wide enough

3 0

2 years ago

Someone help please?

alukav5142 [94]

Answer:

form 1 question????????

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2 years ago

Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5

Bond [772]

Answer:

The solution to the equation system given is:

<u>x = 2</u>
<u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

2x + 3y = 1
3x + y = 5

Following Crammer's Rule, we have the matrix form:

$\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]$

Now we solve using the determinants:

$x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2$

$y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1$

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

2x + 3y = 1
2(2) + 3(-1)= 1
4 - 3 = 1
1 = 1

And, with the second equation:

3x + y = 5
3(2) + (-1) = 5
6 - 1 = 5
5 = 5

4 0

2 years ago