def recursiveFactorial(number):
if number > 0:
return number * (recursiveFactorial(number - 1))
else:
return 1
stringNum = input("Enter a positive integer: ")
num = int(stringNum)
print(recursiveFactorial(num))
I hope this helps!
Answer:
you mind if i take these points?
Explanation:
Which programming language are you working in?
Here is how you could achieve this in Python:
establish a counter, starting at 1.
While your counter is 10 or less, do two things:
print the counter,
and increase the counter by 1.
code:
counter = 1
while counter <= 10:
print(counter)
counter = counter + 1
Those last two lines should be indented.
Answer:
Shows the programming checking if num1 is greater than num2
Explanation:
So num1 and num2 are inputs
for you to code this you would need to put
num1=int(input("What is your first number? ))
and the same for num2 except change num1 for num 2 and first for second
When the input is completed, the computer will check if num 1 is greater than num2
it will do this by using a code something like:
if num1>num2:
Print("Your first input was greater than your second")
But in this example if it greater it just ends
But if it was less than you would put
if num1>num2:
Print("Your first input was greater than your second")
elif num1<num2:
Print("Your first input is less than your second")
So basically this code shows the computer checking if one number is greater than the other or not
