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2 years ago

I need help really bad! I have literally no clue what the answer is to this question

Mathematics

2 answers:

Leya [2.2K]2 years ago

7 0

Answer: C is the answer

kobusy [5.1K]2 years ago

3 0

Answer:

The second answer: {(-1, 4),(2, 7),(3,7)} because every x value has one y value

You might be interested in

Write the factored form of an equation that has the zeros 4 and -7.

sineoko [7]

The factored form of the equation that has the zeros 4 and -7 is y = ( x - 4)( x + 7 ).

<h3>What is the factored form of an equation that has the zeros or roots 4 and -7?</h3>

Roots are simply the points where the graph intercepts with the x-axis. ( y = 0 )
That is, y = 0 the roots

Given the roots of the equation;

4
-7

Now, at x = 4,

x = 4

x - 4 = 0

y = ( x - 4)

Also, at x = -7,

x = -7

x - ( - 7 ) = 0

x + 7 = 0

y = ( x + 7 )

Hence; for the equation with the given roots; 4 and -7 will be;

y = ( x - 4)( x + 7 ).

The factored form of the equation that has the zeros 4 and -7 is y = ( x - 4)( x + 7 ).

Learn more about roots of quadratic equation here: brainly.com/question/26926523

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6 0

2 years ago

In a sample of nequals16 lichen specimens, the researchers found the mean and standard deviation of the amount of the radioacti

GuDViN [60]

Answer:

(a) The confidence level desired by the researchers is 95%.

(b) The sampling error is 0.002 microcurie per millilitre.

Step-by-step explanation:

The mean and standard deviation of the amount of the radioactive element, cesium-137 present in a sample of <em>n</em> = 16 lichen specimen are:

$\bar x=0.009\\s=0.005$

Now it is provided that the researchers want to increase the sample size in order to estimate the mean μ to within 0.002 microcurie per millilitre of its true value, using a 95% confidence interval.

The (1 - <em>α</em>)% confidence interval for population mean (μ) is:

$CI=\bar x\pm z_{\alpha/2}\times \frac{s}{\sqrt{n}}$

(a)

The confidence level is the probability that a particular value of the parameter under study falls within a specific interval of values.

In this case the researches wants to estimate the mean using the 95% confidence interval.

Thus, the confidence level desired by the researchers is 95%.

(b)

In case of statistical analysis, during the computation of a certain statistic, to estimate the value of the parameter under study, certain error occurs which are known as the sampling error.

In case of the estimate of parameter using a confidence interval the sampling error is known as the margin of error.

In this case the margin of error is 0.002 microcurie per millilitre.

(c)

The margin of error is computed using the formula:

$MOE=z_{\alpha/2}\times \frac{s}{\sqrt{n}}$