Answer:
y = (7/2)x -20
Step-by-step explanation:
The given line is in slope-intercept form, so you can read its slope from the equation.
y = mx + b . . . . . m is the slope; b is the y-intercept
y = -(2/7)x + 9 . . . . . . has slope -2/7
The perpendicular line will have a slope that is the negative reciprocal of this, so will be ...
m = -1/(-2/7) = 7/2
We can use this and the given point to write the equation in point-slope form.
y = m(x -h) +k . . . . . . line with slope m through point (h, k)
We have m = 7/2, (h, k) = (4, -6) so the equation is ...
y = (7/2)(x -4) -6
y = (7/2)x -20
Answer:
I think the answer is x = 13/3
Step-by-step explanation:
B. THE 2 IN THE TENTHS PLACE IS 10 TIMES THE VALUE OF THE 2 IN THE HUNDREDTHS PLACE.
2 2 . 2 2 2
tens ones decimal point tenths hundredths thousandths
2 in the tenths place = 0.20
2 in the hundredths place = 0.02
0.02 x 10 = 0.20
Answer to the first question: 7/10ths of a mile
Explaination: When adding fractions, you need to have a common denominator. Since dividing 3/10 by 2 to get a denominator of 5 makes 3 a decimal, it's easier to multiply 2/5 by 2 to get a denominator of 10. You do the same to the top that you do to the bottom: 
. From there, just add 4/10 and 3/10 to get the answer: 7/10ths of a mile.
Answer to the second question: Daniel read three (3/10) more books
Explaination: Since you can't evenly multiply 5 or 2 to get the opposite number, it's easier to multiply to the lowest common multiple. The easiest way to find that is to multiply both denominators (5*2=10). You'll have to multiply the numerator by the same amount you multipled the denominator by. For Daniel, that would mean: 
. For Edgar, that would mean: 
. So, Daniel read 3 more books than Edgar.
Answer to the third question: 2/4 mile (or 1/2 a mile)
Explaination: 2/8 can be simplified, by dividing the top and bottom by 2, resulting in 1/4. Since both fractions have the same denominator (/4), you can add them to get 2/4ths. This can be simplified further to half (1/2) a mile.
Domain: (-infinity, infinity)
range: (-infinity, infinity)
