The answer to your question is y=1
The value of b is -3.
<h3>What is axis of symmetry?</h3>
Axis of symmetry is a line that divides an object into two halves,thereby creation a mirror like reflection of either side of the object.
Now the given function is,
f(x) = 1/4 x^2 bx + 10
and axis of symmetry is at x = 6
Now the quadratic function in standard form is given as,
f(x) = a x^2 bx + c
By comprison we get,
a = 1/4
c = 10
Since axis of symmetry is a vertical line
x = -b/2a
Therefore,
6 = -b/2*(1/4)
-b = 6*2*(1/4)
or, b = -12/4
or, b = -3
Hence,The value of b is -3.
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Answer:

Interval notation: 
Step-by-step explanation:
<u>First inequality:</u>
<u />
Therefore, this inequality restricts:

<u>Second inequality:</u>

Therefore, this inequality restricts:

Therefore, with both of these restrictions together, we have:
.
The solution to the system of equation graphed is (-1, -3)
<h3>Solution to system of equation</h3>
Given the system of equations graphed on the plane expressed as:
f(x) = 3x
g(x) = 4x + 1
Equate
f(x) = g(x)
3x = 4x + 1
3x - 4x = 1
-x = 1
x = -1
Determine the value of y
y = 3x
y = 3(-1)
y = -3
Hence the solution to the system of equation graphed is (-1, -3)
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If it is area your looking for.
Area = product of diagonal lengths divided by 2
Area = 12* 16 /2
=192/2 = 96.
IF it is the side length of the rhombus:
apply Pythagoras theorem since the diagonals always meet at 90°.
L =√(12² + 16²)
L= √400 = 20