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Dovator [93]
2 years ago
11

Due in 20 mins Thank you:)

Mathematics
1 answer:
boyakko [2]2 years ago
6 0

Answer:

the 2nd one..

The only table that represents such a function is table B.'

Step-by-step explanation:

You might be interested in
What is the axis of symmetry of h(x)=5x^2+40x+64
Damm [24]

The axis of symmetry of a parabola is the vertical line passing through its vertex. Given a parabola ax^2+bx+c=0, the vertex x-coordinate can be found using

x = -\dfrac{b}{2a}

In your case, the formula leads to

x = -\dfrac{40}{10} = -4

So, this parabola is symmetric with respect to the line  x = -4

3 0
3 years ago
If x=36 and Y=4, how many of the following are rational numbers?
Savatey [412]

Answer:

2 of them

Step-by-step explanation:

sqr root xy and the sqr rt x/y

5 0
3 years ago
A multiple-choice test consists of 10 questions. Each question has answer choices of a ,b c, d ,e , and , and only one of the ch
aalyn [17]
Its easier to find the complement of that instead
so you find the probability of 1 and 0
The .2 in the answer is the probability of each question 1/5
  (10 C 0) x .2^0 (1-.2)^10-0=.1074
 (10 C 1) x .2^1 (1-.2)^10-1=.2684
.2684+.1074=.3758 and that's the complement
so 1 - .3758= .6242
I too have a stats exam on this tomorrow lol
4 0
2 years ago
Someone pls help, i need to get this right.
Elina [12.6K]

Answer:

0,2

Step-by-step explanation

6 0
3 years ago
Which of the below descriptions shows a possible HAMILTON PATH?
ra1l [238]

Option B: FECBAD represents the Hamilton path

Explanation:

The vertices in the given graph are A,B,C,D,E and F

We need to determine the Hamilton path of the given graph.

By definition, we know that a Hamilton path touches each and every vertex in a graph exactly once.

Hence, we need to connect the vertices in such a way that the graph touches each and every vertex exactly once.

Option A: EFADECBA

From this description, we can see that the path starts from the vertex E and connects all the vertices but some of the vertices are repeated twice.

Hence, the path EFADECBA is not a Hamilton path.

Therefore, Option A is not the correct answer.

Option B: FECBAD

From this description, we can see that the path starts from the vertex F and connects all the vertices exactly once.

Hence, the path FECBAD is the Hamilton path.

Therefore, Option B is the correct answer.

Option C: ADEFBC

From this description, we can see that the path starts from the vertex A and connects all the vertices but the path from F to B has to touch the vertex A. Thus, the vertices are repeated twice.

Hence, the path ADEFBC is not a Hamilton path.

Therefore, Option C is not the correct answer.

Option D: ADECBAFE

From this description, we can see that the path starts from the vertex A and connects all the vertices but some of the vertices are repeated twice.

Hence, the path ADECBAFE is not a Hamilton path.

Therefore, Option D is not the correct answer.

6 0
3 years ago
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