The quotient of 864÷36

Which graph best represents the feasibility region for the system shown above? ( pics are in this)

zalisa [80]

Consider the system of inequalities

$\left\{ \begin{array}{l} y\ge 2 \\ x\le 6 \\ y\le 3x+2 \\ y\le -x+10. \end{array}\right.$

1. Plot all lines that are determined by equalities (see attached diagram)

$\left\{ \begin{array}{l} y=2 \text{ (red line)} \\ x= 6 \text{ (blue line)}\\ y=3x+2 \text{ (green line)} \\ y= -x+10 \text{ (orange line)}. \end{array}\right.$

2. Determine which bounded part of the plane you should select:

$y\ge 2$ means that you should take points with y-coordinates greater than or equal to 2 (top part of the coordinate plane that was formed by the red line);
$x\le 6$ means that you should take points with x-coordinates less than or equal to 6 (left part of the coordinate plane that was formed by the blue line);
for $y\le 3x+2$ you can check where the origin is placed. Since $0\le 3\cdot 0+2$ , the origin belongs to the needed part and you have to take the right part of the coordinate plane that was formed by green line.
for $y\le -x+10$ you can check where the origin is placed. Since $0\le -1\cdot 0+10$ , the origin belongs to the needed part and you have to take the bottom part of the coordinate plane that was formed by orange line.

3. According to the previous explanations, the shaded region is as in A diagram.

Answer: correct choice is A.

5 0

3 years ago

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If Rachel were to paint her living room alone, it would take 2 hours. Her sister Fran could do the job in 5 hours. How many hour

snow_tiger [21]

Rachel and her sister Fran together can paint the living room in $\frac{10}{7}$ hours

Given that

Rachel can paint half of the living room in 1 hour

Fran can paint $\frac{1}{5}$ th part of the living room in 1 hour

Let's assume together they paint the living room in x hours

⇒ together they can paint $\frac{1}{x}$ th part of the living room in 1 hour

By proportions,

⇒ $\frac{1}{2}$ + $\frac{1}{5}$ = $\frac{1}{x}$ {using operation proportions and addition}

⇒ $\frac{7}{10}$ = $\frac{1}{x}$

⇒x= $\frac{10}{7}$

⇒ together they can paint $\frac{7}{10}$ th part of the living room in 1 hour

It means, Rachel and her sister Fran together can paint the living room in $\frac{10}{7}$ hours

Learn more about paint here:

brainly.com/question/15277377

#SPJ9

6 0

1 year ago

-43/100 as a decimal

lutik1710 [3]

Answer:

-0.43

Step-by-step explanation:

100/-43

6 0

3 years ago

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<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

7 0

2 years ago

Solve. t - (- 10) = 9

Gekata [30.6K]

T - ( - 10) = 9
t + 10 = 9
t = 9 - 10
t = -1

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Answer: t = -1
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5 0

3 years ago

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