Question

Find the equation of a line containing the given points. Write the equation in slope-intercept form.

Answer 1

Answer:

y = x + 1

Step-by-step explanation:

(2,3)  (-2, -1)

line equation y - y1 = m (x - x1)

m = (-1 -3) / (-2 - 2)

= -4 / -4 = 1

y - 3 = 1 * (x - 2)

y = x -2 +3

y = x + 1

Answer 2

Answer:

y = 1x+1

Step-by-step explanation:

Slope-intercept form is: y=mx+b

In order to find the slope, or "m" in this formula with two given points, use the slope formula for two coordinates: m= $\frac{y_2-y_1}{x_2-x_1}$.  In this formula, y2 is the second coordinate's y value, y1 is the first coordinate's y-value, and likewise x2 is the second coordinate's x value, x1 is the first coordinate's x-value.

In this problem specifically, we were given coordinates (2,3) and (-2,-1).

This is how those above values would line up:

y2 = -1

x2 = -2

y1 = 3

x1 = 2

Once this is plugged into the formula it becomes $\frac{-1-3}{-2-2}$ , which simplifies to a slope (m) of 1.  

____________________________________________________________

Next to find the y-intercept, or "b" we simply need to plug in a coordinate's values into the slope-intercept form, and I chose (2,3) for simplicity's sake.

This would become (3) = 1(2) + b. Then just solve for b using algebra, which results in a b value of 1.  

The answer is y= 1x +1 which can alternatively be written as y=x+1