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marysya [2.9K]
3 years ago
6

Which of the following values is the 75th percentile?

Mathematics
2 answers:
andre [41]3 years ago
8 0

Answer: Your answer would be C) upper quartile


Step-by-step explanation:


dmitriy555 [2]3 years ago
4 0
C is the answer to you're question. :)

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Phil and Matt made a total of $72.00 selling the cookies. How many cookies
marshall27 [118]

Answer:

36

Step-by-step explanation:

It would only be 36 if they split the amount though

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What is the perimeter of ^PQR with vertices P(-2,9) Q(7,-3) and R(-2,-3) in the coordinate plane?
e-lub [12.9K]
Using the distance formula we can determine the perimeter of PQR.

Distance formula: d=√(x-x1)^2+(y-y1)^2
distance of PR: √(-2+2)^2+(9+3)^2= 12
distance of QR: √(7+2)^2+(-3+3)^2=9
distance of PQ: √(7+2)^2+(-3-9)^2= 15

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3 years ago
Adi used algebra tiles to represent the product (negative 2 x minus 1)(2 x minus 1). An algebra tile configuration. 4 tiles are
Hunter-Best [27]

Answer:

Step-by-step explanation:

c

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Arte-miy333 [17]
This pic shows the ans

7 0
3 years ago
A CHICKEN COOP HOLDS A TOTAL OF 10 HENS OR 20 CHICKS. IF 2/5THS OF THE HENS IN A FULL COOP ARE REMOVED, HOW MANY NEW CHICKS COUL
LiRa [457]

Answer:

8 new chicks can be fitted in the coop.

Step-by-step explanation:

A chicken coop holds 10 hens or 20 chicks.

That means space in the coop for 10 hens = space for 20 chicks

Or space for 1 hen = space for 2 chicks

Now \frac{2}{5}th of the hens were removed from the coop.

So, number of hens removed from the coop = \frac{2}{5}\times 10

= 4 hens

And space for 4 hens in the coop = space for the 8 chicks

Therefore, 8 new chicks can be fitted in the coop.

5 0
3 years ago
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