All categories

3 years ago

5. Find the length of the arc. Use 3.14 for the value of t Round your answer to the nearest tenth.

Mathematics

1 answer:

Rufina [12.5K]3 years ago

7 0

Answer:

the answer is 12.4cm

brainliest?

You might be interested in

I need help What is the surface area of the following figure? A 168 B 192 PLEASE HELP

Juliette [100K]

Answer:

Step-by-step explanation:

First step is always to break up the problem into parts and write out our formulas- in this case, let's solve the easier part first, the bottom rectangular box type shape.

Area of a square or rectangle: A= length * height

Area of a triangle: A = 1/2 * length * height

Each side is 6x2, making each side 12 in^2, times four sides equals 48 in^2

The box also has a bottom, with dimensions of 6x6, equaling 36 in^2. <em>be careful not to include the top, it may be included in this part of the problem that we're splitting up, but it's not in the actual figure</em>.

Next up is the top portion- let's calculate the two triangular sides first. again, A=(1/2)l*h . so, these triangles are (1/2) * 5 * 4 , or 10 in^2 . With two triangular sides that's 20 in^2 total.

And now we only have two sides left, the rectangular parts of the triangular prism. They have a dimension of 5*6, equalling 30, and with two sides its a total of 60 in^2.

All of these sides can be added together:

48 + 36 + 20 + 60 = 305 in^2

3 0

3 years ago

Read 2 more answers

72 is 75 percent of what number

aniked [119]

Its ans will become 96

3 0

3 years ago

Read 2 more answers

Choose the solution set represented by the following graph

Juliette [100K]

The answer to the question is the first one

7 0

3 years ago

In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg.

muminat

Answer:

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are $m= 1.0\ kg$

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

Let initial velocity of ball $A\ is\ u_1$
Initial velocity of ball $B\ is\ u_2$
Final velocity of ball $A\ is\ v_1$
Final velocity of ball $B\ is\ v_2$
Momentum before collision $= mu_1+mu_2$
Momentum after collision $=mv_1+mv_2$

Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

$mu_1+mu_2=mv_1+mv_2$

We will plug each trial to this equation.

Trial 1

$mu_1+mu_2=mv_1+mv_2\\1.0(1)+1.0(-2)=1.0(-2)+1.0(-1)\\1-2=-2-1\\-1=-3$

Trial 2

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1.5)=1.0(-.5)+1.0(-\.5)\\.5-1.5=-.5-.5\\-1=-1$

Trial 3

$mu_1+mu_2=mv_1+mv_2\\1.0(2)+1.0(1)=1.0(1)+1.0(-2)\\2+1=1-2\\3=-1$

Trial 4

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1)=1.0(1.5)+1.0(-1.5)\\.5-1=1.5-1.5\\-.5=0$

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

5 0

3 years ago

Determine the factors of X2 -12 X -20

mafiozo [28]

Answer:

It doesn't factor nicely

Step-by-step explanation:

x = 13.48331477, -1.483314774

4 0

3 years ago