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Westkost [7]
3 years ago
8

What is the most common type of biconditional?

Mathematics
1 answer:
natulia [17]3 years ago
5 0

Step-by-step explanation:

<em>If I have a pet goat, then my homework will be eaten. </em>

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Use the pythagoren theorem to solve x
defon
Well the equation is (A^2)+(B^2)=(C^2)

A= x
B= 2x
C will always be the longest side because it is the Hypotenuse = 25

So if you plug in those numbers into the equation...

(x^2) + (2x^2) = (25^2)

x^2 + 4x^2 = 625

Combine like terms

5x^2 = 625

Divide by five to both sides

x^2 = 125

Then Square root,

x = sqrt(125)

x = sqrt(25* 5)

x = 5sqrt(5)
3 0
4 years ago
Todea what did one pencil say to another mathematics algebra order of operations answer
Serjik [45]
Part 1

6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)}  \\  \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\  \\ =3



Part 2

7-8\div4(3^2-1)=7-8\div4(9-1) \\  \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\  \\ =6  \frac{1}{2} = \frac{13}{2}



Part 3

2-2(2-5)^2+3^2=2-2(-3)^2+9 \\  \\ =2-2(9)+9=2-18+9=-7



Part 4

(5^2-9\cdot3)^2-11=(25-27)^2-11 \\  \\ =(-2)^2-11=4-11=-7



Part 5

[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\  \\ =(1-5)\cdot4=-4\cdot4=-16



Part 6

12-11\cdot2+16\div8=12-22+2 \\  \\ =-8



Part 7

-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\  \\ =-2-(-1)=-2+1=-1



Part 8

8+2\cdot3-14\div7=8+6-2 \\  \\ =12



Part 9

(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\  \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\  \\ =36+4=40



Part 10

7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\  \\ =7+(-7)\cdot5=7+(-35)=7-35 \\  \\ =-28



Part 11

3-2[2^3+(-1)^3]=3-2[8+(-1)] \\  \\ =3-2(8-1)=3-2(7)=3-14 \\  \\ -11



Part 12

18+6\div3(2^2+5)=18+6\div3(4+5) \\  \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\  \\  =18 \frac{2}{9}
8 0
4 years ago
2/3*x+3/4=8 what is x
matrenka [14]

Answer: x=10 7/8

Step-by-step explanation:

Subtract 3/4 from both sides. Multiply both sides by 3. Divide both sides by 2 (basically just isolate x on one side of the equal sign).

7 0
3 years ago
Kevin has just purchased a small rectangular fish tank that holds 904.5 milliliters of water. The tank has a length of 15 cm and
Nitella [24]

Answer:

A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?

Step-by-step explanation:

A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?

5 0
3 years ago
NO LINKS!!! PLS HELP ME IM TRYING TO GRADUATE PLSSS !!! Find the midpoint of the segment below and enter its coordinates as an
Leto [7]

Answer:

x = 5/2 , y = -7/2

Step-by-step explanation:

<em>r's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>finding</em><em> </em><em>midpoint</em><em> </em><em>=</em><em>.</em><em>(</em><em> </em><em>X1</em><em> </em><em>+</em><em> </em><em>X</em><em>2/</em><em>)</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>(</em><em>Y1+</em><em>Y2)</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> </em><em>the </em><em>value</em><em> </em><em>of </em><em>in </em><em>formula</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>x=</em><em> </em><em> </em><em>4</em><em>+</em><em>1</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>1</em><em>-</em><em>6</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>7</em><em>/</em><em>2</em>

<em>hope</em><em> it</em><em> helps</em>

3 0
3 years ago
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