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2 years ago

Please help i’ll give brainliest

Mathematics

1 answer:

Setler79 [48]2 years ago

7 0

Answer:

range

Step-by-step explanation:

*JUST AND EDUCATED GUESS* but id say range

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Can someone help me? IN NEED OF HELP!

bearhunter [10]

Answer:(updated)

2.4%

Step-by-step explanation:

$2.90-$2.83=$.07

.07/2.9=0.024137931(round to nearest ten<u>th</u>)=2.4%

or you can do 0.024137931*100 and get the same answer

Shout out to lameash66 (they helped me change my answer, thank you)

8 0

3 years ago

Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = 7 divided by q and tan y° =

Andre45 [30]

Answer:

Cosy° = $\frac{r}{q}$

Step-by-step explanation:

From the picture attached,

By applying all trigonometric ratios in the given right triangle,

Siny° = $\frac{7}{q}$ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

tany° = $\frac{7}{r}$ = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

Therefore, Cosy° = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

Cosy° = $\frac{r}{q}$

Therefore, Cosy° = $\frac{r}{q}$ will be the answer.

5 0

3 years ago

20×+4=4(5x+1) how many solution are in this equation

Tomtit [17]

Simplify both sides of the equation

(20)(4)= 4(5x+1)

Simplify

80 = 20x+4

Flip the equation

20x+4 = 80

Subtract 4 from both sides

20x+4-4 = 80-4

20x = 76

Divide both sides by 20

20x/20 = 76/20

x= 3.8

There is one solution in this equation

7 0

3 years ago

Find the integral, using techniques from this or the previous chapter.<br> ∫x(8-x)3/2 dx

Soloha48 [4]

Answer:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

Step-by-step explanation:

For this case we need to find the following integral:

$\int x(8-x)^{3/2}dx$

And for this case we can use the substitution $u = 8-x$ from here we see that $du = -dx$ , and if we solve for x we got $x = 8-u$ , so then we can rewrite the integral like this:

$\int x(8-x)^{3/2}dx= \int (8-u) u^{3/2} (-du)$

And if we distribute the exponents we have this:

$\int x(8-x)^{3/2}dx= - \int 8 u^{3/2} + \int u^{5/2} du$

Now we can do the integrals one by one:

$\int x(8-x)^{3/2}dx= -8 \frac{u^{5/2}}{\frac{5}{2}} + \frac{u^{7/2}}{\frac{7}{2}} +C$

And reordering the terms we have"

$\int x(8-x)^{3/2}dx= -\frac{16}{5} u^{\frac{5}{2}} +\frac{2}{7} u^{\frac{7}{2}} +C$

And rewriting in terms of x we got:

$\int x(8-x)^{3/2}dx= -\frac{16}{5} (8-x)^{\frac{5}{2}} +\frac{2}{7} (8-x)^{\frac{7}{2}} +C$

And that would be our final answer.

8 0

2 years ago

What is the cube root of 64i

Rus_ich [418]

Answer:

Step-by-step explanation:

3 0

3 years ago