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umka2103 [35]
4 years ago
9

1 + 44=?????? I NEED HELPPP

Mathematics
1 answer:
Alenkinab [10]4 years ago
4 0

Answer:

45

Step-by-step explanation:

1. Create an Equation

In this case, the equation has been given in the problem.

2. Re-Arrange / Simplify your Equation

Add the numbers 44 + 1. In a horizontal view, it may be easier to convert this equation into a vertical format:

         44

                 +

           1

_______

       

3. Solve your Equation

Now that the equation has been simplified, it's much easier to solve.

         44

                 +

           1

_______

        45

The answer should be 45.

Alternative Solution:

1. Convert the equation into units.

You can choose to view 44 + 1 as units. If you add 44 units to 1 unit, then you will have 45 units in total.

I hope this helped and cleared up any confusion!

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Kiana is saving for a new computer that cost $499. So far, she has earned 68 percent of the cost of the computer. How much more
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Answer:

159.68

Step-by-step explanation:

68% of 499 is 339.32

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6 0
3 years ago
Solve the equation <br> 6 - ( 3 - c ) = 2
Andreas93 [3]

Answer:

c = -1

Step-by-step explanation:

6 - (3 - c) = 2

6 - 3 + -(-c) = 2

3 + c = 2

c = 2 - 3

c = -1

Check:

6 -(3-(-1)) = 2

6 - (3+1) = 2

6 - 4 = 2

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The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen
vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.75

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X = 9) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is P(X \geq 16) when n = 20

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897

P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339

P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669

P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211

P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032

So

P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

E(X) = np

In this question, we have n = 22

So

E(X) = 22*0.75 = 16.5

The closest integer to 16.5 is 17.

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