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3 years ago

Can somebody explain what I have to do to find the value of x? (In the pic)

Mathematics

2 answers:

schepotkina [342]3 years ago

4 0

Their on a line and a line = 180 so you ether =them to 180 or to each other so if you want the answer hold on a sec

gladu [14]3 years ago

3 0

X=16.8 i think, i'm bad at math sorry

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Solve the decimal division application round to the nearest 10th if needed there are approximately 39.37 inches in 1 m determine

Shtirlitz [24]

Answer:

D. 1000 meters

Step-by-step explanation:

(39370 in)/(39.37 in/m) = (39.37×1000)/(39.37) m = 1000 m

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3 years ago

1:The bee hummingbird is the smallest species. It

olasank [31]

1.7x 10 =17

Hope this helps

3 0

3 years ago

(a) Each student in a pottery class is responsible for cleaning the area around his or her workspace at the end of the lesson. E

ArbitrLikvidat [17]

Ok this is not as hard as it seems

(4.5 feet)^2 times the number of students (13)

20.25 x 13

263.25 is the correct answer

I hope it helps :<

5 0

3 years ago

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Leviafan [203]

$\qquad\qquad\huge\underline{{\sf Answer}}$

$\textbf{Since it's a right angled Triangle we can } \\ \textbf{ use Pythagoras theorem }$

$\sf{Cos (29°) = \dfrac{b}{c}}$

$\sf{Cos (29°) = \dfrac{b}{260}}$

$\sf{b= 260\cdot Cos (29°) }$

$\sf{b= 260\cdot 0.875 }$

[ $\textsf{Cos(29°)= 0.875}$ ]

$\sf{b= 227.5 in }$

$\textsf{I hope you understood the procedure}$

7 0

2 years ago

David is going to install tiles on the floor of two rooms. One of the floors is 18 feet long by 12 feet wide. The other floor is

crimeas [40]

Dimension of one of the floors of one room that David wants to install tiles is 18feet long by 12 feet wide
Then
Area of the above room = 18 * 12 square feet
   = 216 square feet
Dimension of the floor of the other room that David wants to install tiles is 24 feet long and 16 feet wide
Then
Area of the other room = 24 * 16 square feet
   = 384 square feet
Then
The total square feet of the
rooms that David wants to install tiles = 216 + 384
   = 600 square feet
Cost of the tile that covers 1 square feet = $5
Cost of the 4 tiles that cover 4 square feet = $17
Then
Area that can be covered with 4 square feet of tiles = 600/4 square feet
      = 150 square feet
Minimum cost of covering
the two rooms that David wants to install tiles = 150 * 17 dollars
      = 2550 dollars
So the minimum cost of installing the tiles on the two floors of David's two rooms is $2550. I hope the procedure is simple enough for you to understand.

8 0

3 years ago