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Inessa [10]
2 years ago
7

The company estimated that they would sell 500 caps during the football season. They actually sold 575. Find the percent error.

Round to the nearest tenth.​
Mathematics
1 answer:
Paraphin [41]2 years ago
5 0

Answer:  

13.1%

Step-by-step explanation:  

The company estimated that there would be 500 a ps during the football season

The actually sold 575

Therefore the percent error can be calculated as follows

= 575-500/575 × 100

= 75/575 × 100

= 0.1304×100

= 13.1%

Hence the percent error is 13.1%

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Need help please help
andriy [413]

-1/3

Or, -0.3333333...

8 0
3 years ago
I NEED THE ANSWER RIGHT NOW PLEASE!!!
strojnjashka [21]

Answer:

Second : 1/6 x + 47

Third : 1 2/3 x + 35 - 1 1/2 x + 12

Fourth : 5 (1/3x) + (5) (7) - (3) (1/2x) + (3) (4)

Step-by-step explanation:

I would start by expanding the expression, showing each step. Then, simplify by collecting like terms.

To expand, you multiply the term outside of the brackets by each term inside the brackets.

5(1/3x + 7) - 3(1/2x - 4)

= 5(1/3x) + (5)(7) - (3)(1/2x) + (3)(4)       Showing how to expand

= 5/3x + 35 - 3/2x + 12           Simplified above step by multiplying

= 5/3x - 3/2x + 47            Collected like terms (35 + 12 = 47)

= 10/6x - 9/6x + 47          Change fractions to the common denominator 6

= \frac{10-9}{6}x + 47   Combine fractions with common denominator

= 1/6x + 47              Fully expanded

See which options match the steps I took to expand the original expression.

The second step is the same as option 4.

The last step is the same as option 2.

I bolded those steps that are the same.

Some options use mixed fractions (whole numbers and fractions).

From the third step, I will convert the improper fractions to mixed fractions.

5/3x + 35 - 3/2x + 12

= 1 2/3x + 35 - 1 1/2x + 12

This is the same as option 3.

\frac{5}{3}x = 1\frac{2}{3}x    On the left side, 5 goes into 3 ONE time. The ONE becomes the whole number. After 5 goes into 3, there is 2 left, which becomes the numerator.

\frac{3}{2}x = 1\frac{1}{2}x   On the left side, 3 goes into 2 ONE time. The ONE becomes the whole number. The remainder is 1, which becomes the numerator.

6 0
3 years ago
Read 2 more answers
105.25 x 70.75<br><br><br> NO LINKS!!!!!
Anarel [89]

Answer:

7446.4375

Step-by-step explanation:

  105.25

x   70.75

-------------

 52625

First, we will want to start with the hundredths place. multiply 5×5. We get 25. Put the 5 down and carry the 2 above 2 in 105.25. Next, we multiply 2 in 105.25 with 5 in 70.75. 2×5 is 10, then we add the carried 2, and 10+2 is 12. We put the 2 down below, and carry the 1 above 5 in 105.25. Next, we multiply the 5 in 105.25 times 5. 5×5 is 25. We then need to add the carried 1 to 25 to get 26. We put the 6 down and put the 2 over 0 in 105.25. Next, we multiply 0 in 105.25 with 5 in 70.75. 0×5 is 0, plus our carried 2 from before, so 2. We don't need to carry anything since it's only the ones digit, so we put the 0 down. Next, we multiply the 1 in 105.25 with 5 again in 70.75. 1×5=5. Since we have no carries we can put the 5 down without adding anything. If this seemed confusing, let me simplify it for you. You basically start with the bottom number's "digit". For us, that's 70.75, and 5 would be the "digit." (The last digit from the bottom number.) We then multiply this "digit" by every number from the top number's digits. For example, we'd multiply 70.75's 5, with 105.25's 5 first, then continue on going left from there. I hope this helped! If it just confused you more please let me know.  (Also remember to put a 0 when you start multiplying with your second digit on the bottom number)

3 0
3 years ago
In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad
weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

\angle acd = 60 ^{\circ}

Therefore, we have

\angle dcb =90- 60= 30 ^{\circ}

Now, in triangle bcd, we have

\tan30 = \frac{5}{cd}\\&#10;\\&#10;\frac{1}{\sqrt 3}=\frac{5}{cd}\\&#10;\\&#10;cd=5\sqrt 3

Now, in triangle acb, we have

tan 60 = \frac{ad}{5\sqrt3} \\&#10;\\&#10;\sqrt 3=  \frac{ad}{5\sqrt3}\\&#10;\\&#10;ad= 5\sqrt3 \times \sqrt 3\\&#10;\\&#10;ad= 5\times 3\\&#10;\\&#10;ad=15

Thus, ad is 15 cm.


4 0
3 years ago
Evaluate the following division: (3b-6a)÷(30a-15b)​
shutvik [7]

Evaluate the following division: (3b-6a)÷(30a-15b) is <u>-</u><u>1</u><u>/</u><u>5</u><u>.</u>

<h2><u>INTRODUCTION</u></h2>

~ Algebraic Forms and their Elements

Algebraic form is a mathematical form whose presentation involves symbols or letters to represent unknown numbers.

Elements of Algebra:

1. Variables, Constants and Coefficients

Pay attention to the algebraic form 3x + 2y + 3

From the algebraic form above, x and y are variables (variables), while the number 3 is a constant. A variable is a substitute symbol for a number whose value is not clearly known. While constants are terms of an algebraic form in the form of numbers and do not contain variables.

And what is meant by the coefficient is the constant factor of a term in algebraic form. The coefficient on the 3x term is 3, on the 2y term it is 2.

2. Terms and Factors

» The term is part of the algebraic form which is limited by the operation of addition (+) or difference (-). The term one is an algebraic form that is not connected by the operation of addition or difference.

Example: 2x, 2a², -4xy, . . .

» Term two is an algebraic form that is connected by an operation of sum or difference.

Example: 2x + 3, a² - 4, 3x² - 4x, . . .

» Similar terms in algebraic form are terms that have the same variable and the same power.

Example:

2a is similar to 3a, 4a, etc.

» Factors are part of the algebraic form that is restricted to multiplication operations.

Example: 5n = 5 × n, 5 and n are factors of 4n, respectively.

Calculation Operations on Algebraic Forms

1. Addition and subtraction of algebraic forms can only be done on similar terms.

2. Multiplication and division of algebraic forms.

Multiply two terms by constants or variables.

Example:

3 (4y + 5)

= (3 × 4y) + (3 × 5)

= 12y + 15

Division of two terms with a variable or constant, for example:

(8y+4)/2 = 8y/2 + 4/2 = 4y + 2

<h2><u>DISCUSSION</u></h2>

(3b-6a)÷(30a-15b)

= (-6a + 3b) ÷ (-5(-6a+3b))

= (-6a+3b)/(-5(-6a+3b))

= -1/5

<h3>Conclusion:</h3>

So, Evaluate the following division: (3b-6a)÷(30a-15b) is -1/5.

<h3>Learn More:</h3>

(mampir ke indo:v)

  1. Algebraic subtraction material: https://brainly.co.id/task/35216852
  2. Algebraic arithmetic operations: https://brainly.co.id/task/26250852
  3. The equation of the value of x in algebraic form: https://brainly.co.id/task/42124780

_____________

<h3>Answer Details:</h3>

Class: 7 Middle School

Subject: Math

Material: Chapter 2.1 -Operations of Algebraic Forms

Categorization Code: 7.2.2.1

Keywords: Simple form of algebra

7 0
2 years ago
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