These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
Answer:
h = 
- r
Step-by-step explanation:
The question requires you to make h the subject of the formula.
S = 2πrh + 2πr²
subtract 2πr² on both sides.
S - 2πr² = 2πrh - 2πr² - 2πr²
S - 2πr² = 2πrh
Dividing both sides by 2πr
(S - 2πr²)/2πr = 2πrh/ 2πr
h = - r
Answer:
1^15 is 15
Step-by-step explanation:
Answer:
1.5225 gumbo squared
Step-by-step explanation:
First we know that 1 gumbo is equal to 8.5 lollygams.
To know the number of gumbo squared in 110 lollygam squared, we need to know the relation between 1 gumbo squared and 1 lollygam squared, and we do that making the square of our relation between gumbo and lollygams:
1 gumbo -> 8.5 lollygams
1 gumbo squared -> (8.5)^2 lollygams squared = 72.25 lollygams squared
Now, to know the number of gumbo squared in 110 lollygam squared, we just need to divide 110 by 72.25:
1 gumbo squared -> 72.25 lollygams squared
x gumbo squared -> 110 lollygams squared
x = 110/72.25 = 1.5225 gumbo squared
Answer:
Area of a trapezoid is found with the formula, A=(a+b)/2 x h
Step-by-step explanation:
