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il63 [147K]
3 years ago
7

Help me pls i need this right now pls HELP IF YOU DONT KNOW DONT ANSWER LUV U <33

Mathematics
2 answers:
tino4ka555 [31]3 years ago
6 0

Answer:

What is the question?

Step-by-step explanation:

Zina [86]3 years ago
4 0

Answer:

what is the question? lol

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Using the graph below, what is the value of f(6) ?
Dima020 [189]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f(6) =   - 2

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5 0
3 years ago
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Help me on my question please <br><br> Giving Brainlist
astra-53 [7]

Answer:

0.8

Step-by-step explanation:

5 0
2 years ago
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Can someone help me with these two please , i’ll cashapp
Pavel [41]
3. 180 - (53+68) = 59

The answer is B. 59°

4.
Part A: The measure of a is 70°.

Explanation: The angle sum in any triangle is 180°. 70 + 40 is 110. To find the final angle, subtract 110 from 180. 180 - 110 = 70

Part B: The length of x is 5m.

Explanation. The triangle is an isosceles triangle. We know this because the two angles on the base are equal. Since this is an isosceles triangle, the two longer sides are the same length. Therefore: x = 5 m.
5 0
3 years ago
Simply the attached question​
Finger [1]

Answer:

=x⁴−x³−14x²

Step-by-step explanation:

<h3>Let's simplify step-by-step.</h3>

x²(3x²+5x−4)−2x²(x²+3x+5)

<h3>Distribute:</h3>

=(x²)(3x²)+(x²)(5x)+(x²)(−4)+−2x⁴+−6x³+−10x²

=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²

<h3>Combine Like Terms:</h3>

=3x⁴+5x³+−4x²+−2x⁴+−6x³+−10x²

=(3x⁴+−2x⁴)+(5x³+−6x³)+(−4x²+−10x²)

=x⁴+−x³+−14x²

<h3>ANS-</h3>

=x⁴−x³−14x²

6 0
2 years ago
Photo above need help
Ira Lisetskai [31]

Answer:

m = 0

Step-by-step explanation:

<u>If two lines are parallel, their slopes are equal. </u>

The slope of x - axis is 0

(why?)

because, slope of a line is given by

\boxed{\mathsf{slope\:of\:a\:line=tan \theta}}

Θ is the angle made by the line with the x- axis.

Here, the line in question is the x- axis itself, and every line makes an angle of 0° with itself.

=> Θ = 0

=> tan Θ = 0

=> slope = 0

and the line in blue is parallel to the X- axis, therefore, it's slope is also 0

(also, a line makes an angle of 0° with the line it's parallel to)

<u>                                </u>

\mathfrak{\overline{There\:You\:Are!}}

6 0
2 years ago
Read 2 more answers
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