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geniusboy [140]
3 years ago
11

Is there a difference between stomata and lenticels?

Biology
1 answer:
Natali [406]3 years ago
4 0
Stomata is present at epidermis of the leaves  lenticels are present at bark 
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Question 12
Ludmilka [50]

Answer:

The answer is D: Recombinant DNA is produced by pasting together DNA from two sources

Explanation:

Recombinant DNA, or rDNA, is made by pasting together 2 halves of DNA strands from different sources

8 0
2 years ago
Mars has ice caps containing frozen CO2 and H2O, and little to no atmosphere. It’s lack of atmosphere causes it to very hot in t
frozen [14]

Answer:

d

Explanation:

4 0
2 years ago
What are substrates in biology
torisob [31]

Answer:1 : substratum. 2 : the base on which an organism lives the soil is the substrate of most seed plants. 3 : a substance acted upon (as by an enzyme)

4 0
2 years ago
Explain how the shape of a protein molecules can affect its function
kherson [118]

Solution:

The function of a protein is determined by its shape.

The shape of a protein is determined by its primary structure (sequence of amino acids).

The sequence of amino acids in a protein is determined by the sequence of nucleotides in the gene (DNA) encoding it.

7 0
3 years ago
A man who is an achondroplastic dwarf with normal vision marries a color-blind woman of normal height. The man's father was six
Degger [83]

Answer:

1/4.

Explanation:

The autosomal dominant trait means that the trait is visible in homozygous dominant and in heterozygous condition. The X linked recessive trait will be pass down from mothers to their sons and daughters will show the trait in homozygous recessive condition only.

The man is achandroplastic dwarf ( Aa) with normal vision (XY ) is married with woman that has normal height (aa) with color blind (XhXh). They have a daughter who is dwarf ( Aa). The probability of being dwarf can be calculated by the cross Aa × aa. The offspring are Aa, Aa, aa, aa. Means 1/2 are the probability of being hetterozygous for achondroplastic . The vision probability is calculated by cross XY and XhXHh. The probability that female is heterozygous is 1/2.

So, the heterozygous probability for both trait is 1/2× 1/2 = 1/4.

3 0
3 years ago
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