How many solutions can be found for the system of linear equations represented on the graph?

Mathematics

1 answer:

Iteru [2.4K]3 years ago

5 0

Answer:

A) No solution

Step-by-step explanation:

Given the systems of linear equations, y = 2x + 1 and y = 2x - 1:

Both equations in the system have the same slope, m = 2, thus forming parallel lines. Since their lines are parallel from each other, then it means that their lines will never intersect.

Therefore, the given systems of linear equation is an <u>inconsistent system</u> that has no solution.

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Answer:

1st choice Music Equation: $\$(x+5)$

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Solution: 2

Step-by-step explanation:

Given that:

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5 0

3 years ago

Can someone solve for x

Helen [10]

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$\bf |x^2-4x-5|=7\implies \begin{cases} +(x^2-4x-5)=7\\\\ -(x^2-4x-5)=7 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(x^2-4x-5)=7\implies x^2-4x-5=7\implies x^2-4x-12=0 \\\\\\ (x-6)(x+2)=0\implies x= \begin{cases} 6\\ -2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ -(x^2-4x-5)=7\implies x^2-4x-5=-7\implies x^2-4x+2=0 \\\\\\ (x-2)(x-2)=0\implies x = 2$