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nadezda [96]
2 years ago
11

The length of a rectangle is 5 more than twice the width. Which equation could represent the area of the rectangle in terms of t

he width?
Mathematics
2 answers:
Daniel [21]2 years ago
6 0

A=lw

w=width

2w+5=length

42=w(2w+5)

42=2w2+5w

2w2+5w-42=0

use the quadratic equation

(-5+√25+336)/4

(-5+√361)/4

(-5+19)/4

14/4=3.5

w=3.5 m

2w+5=12 m

3.5 by 12 rectangle

liq [111]2 years ago
5 0

Answer:

l=5+2w

Step-by-step explanation:

Since the length is twice the width plus 5, the equation would look like :

l=5+2w

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Solve each of the following for the indicated variable.a. 9 − 6 = 54 for yb. = 2 + 2 for l
marta [7]

Answer:

\begin{gathered} y=\frac{9}{6}x-9 \\ l=\frac{P}{2}-w \end{gathered}

Step-by-step explanation:

To solve the following equations, we need to isolate the variable asked using inverse operations to solve equations.

Remember that addition and subtraction are inverse operations, as multiplication and division.

Therefore,

\begin{gathered} a\text{. Solve for y} \\ 6y=9x-54 \\ y=\frac{9}{6}x-\frac{54}{6} \\ y=\frac{9}{6}x-9 \end{gathered}\begin{gathered} b\text{. Solve for l} \\ P=2l+2w \\ 2l=P-2w \\ l=\frac{P}{2}-\frac{2}{2}w \\ l=\frac{P}{2}-w \end{gathered}

4 0
1 year ago
Al sumar fracciones con igual denominador, debemos sumar numerador con numerador y denominador con denominador. Verdadero o fals
Ahat [919]

Answer:

La respuesta es falso.  

Step-by-step explanation:

La respuesta es falso.  

Cuando se suman fraccciones con igual denominador, se suman los numeradores (numerador con numerador) y se deja el mismo denominador (el cual es común en ambos). Por ejemplo, la suma de 1/5 + 3/5 da como resultado:    

\frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} = \frac{4}{5}

En el caso de fracciones con diferentes denominadores, tampoco se suma numerador con numerador y denominador con denominador. En ese caso se debe encontrar el mínimo común múltiplo.

 

Por lo tanto, la respuesta es falso.

Espero que te sea de utilidad!

7 0
2 years ago
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