What you would do is you would substitute each ordered pair into their respective variables. (ie. for (0,1) you would put 0 where the x is and 1 where the y is) You would then solve the equation. If the equation is not even (ie. 2=5 would not be even but 4=4 would be), you move on to the next ordered pair.
If you follow the process right and you get the equations correct, the answer should be B. (7,-2)
use this formula Sn=n/2[2a+(n-1)d]
here,d=a2-a1 and n= no. Of terms
Step-by-step explanation:
S8=8/2[2(1)+(8-1)2]
S8=64
Answer:
The answer to your problem is 2.
Step-by-step explanation:
Answer:
Option C is correct
Step-by-step explanation:
The common difference is 10,
So, the function is f(n + 1) = f(n) + 10 , where f(1) = 14
The recursive function for the arithmetic sequence is given by:
.....[1]
where d is the common difference of the two consecutive terms.
Given the arithmetic sequence :
14, 24, 34, 44, 54, .......
First term f(1) = 14
Common difference(d) = 10
Since,
24 -14 = 10
34-24 = 10
44-34 = 10 and so on....
Substitute d = 4 in [1], we have;
Therefore, the recursive function used to generate the sequence is,
and f(1) = 10
