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3 years ago

PLZZZ HURRYYY ILL GIVE YOU BRAINIEST What are the x-intercepts?

Mathematics

1 answer:

Alinara [238K]3 years ago

6 0

Answer:

The x-intercepts are 0, 1, 2, 2.2

Step-by-step explanation:

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What was the percent decrease in the price of MegaTek (MGTK) stock during the market decline of March 1, 2001, to March 1, 2002?

GuDViN [60]

Answer:

Insufficient data.

Step-by-step explanation:

Here, we need to find the percent decrease in the price of the stock during the market decline of March 1, 2001, to March 1, 2002,

i.e $\frac{\text{Price of stocks on 1 March 2001 - Price of stock 1 March 2002}}{\text{Price on 2001}}\times 100$

(1)

∵ The price of the stock during March 1, 2001 = $56.20,

So, the percentage decrease = $\frac{56.20 - \text{Price of stock March 1, 2002}}{\text{Price on 2001}}\times 100$

Thus, data is insufficient to find the percentage decrease.

(2) ∵ The price of the stock during January 1, 2002 = 1 quarter of $56.20,

$=\frac{1}{4}(56.20)$

= $ 14.05

i.e. we have neither price in 1 march 2001 nor price in 1 march 2002.

Thus, data is insufficient to find the percentage decrease.

Even we combined the statements (1) and (2),

The data is insufficient to find the percentage decrease.

7 0

3 years ago

On a store counter are exactly two boxes containing only purple marbles and yellow marbles. Box A has 30 purple marbles and 20 y

klemol [59]

Answer: Our required probability would be 0.35.

Step-by-step explanation:

Since we have given that

Number of boxes = 2

Number of purple marbles in Box A = 30

Number of yellow marbles in Box A = 20

Number of purple marbles in Box B = 15

Number of yellow marbles in Box B = 35

So, If Melanie randomly selects one of the boxes and then randomly selects one marble from that box.

Probability that the marble selected will be purple is given by

$\dfrac{1}{2}\times \dfrac{20}{50}+\dfrac{1}{2}\times \dfrac{15}{50}\\\\=\dfrac{1}{2}(\dfrac{20+15}{50})\\\\=\dfrac{1}{2}\times \dfrac{35}{50}\\\\=\dfrac{35}{100}\\\\=0.35$

Hence, our required probability would be 0.35.

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3 years ago

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Anna35 [415]

Answer:452.38934211693

Step-by-step explanation:

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2 years ago

I need help now if baby yoda is to live in the next episode in Mandalorian

Nady [450]

Answer:

1. 52*

2. 128* ( I think)

Step-by-step explanation:

3 0

3 years ago

Consider a sampling distribution with p equals 0.15p=0.15 and samples of size n each. Using the appropriate formulas, find the

Grace [21]

Answer:

$a.\ \mu_p=750\ \ , \sigma_p=0.005\\\\b.\ \mu_p=150\ \ , \sigma_p=0.0113\\\\c.\ \mu_p=75\ \ , \sigma_p=0.0160$

Step-by-step explanation:

a. Given p=0.15.

-The mean of a sampling proportion of n=5000 is calculated as:

$\mu_p=np\\\\=0.15\times 5000\\\\=750$

-The standard deviation is calculated using the formula:

$\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\=\sqrt{\frac{0.15(1-0.15)}{5000}}\\\\=0.0050$

Hence, the sample mean is μ=750 and standard deviation is σ=0.0050

b. Given that p=0.15 and n=1000

#The mean of a sampling proportion of n=1000 is calculated as:

$\mu_p=np\\\\=1000\times 0.15\\\\\\=150$

#-The standard deviation is calculated as follows:

$\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.15\times 0.85}{1000}}\\\\\\=0.0113$

Hence, the sample mean is μ=150 and standard deviation is σ=0.0113

c. For p=0.15 and n=500

#The mean is calculated as follows:

$\mu_p=np\\\\\\=0.15\times 500\\\\=75$

#The standard deviation of the sample proportion is calculated as:

$\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.15\times 0.85}{500}}\\\\\\=0.0160$

Hence, the sample mean is μ=75 and standard deviation is σ=0.0160

4 0

3 years ago