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nevsk [136]
3 years ago
8

HELP ME OUT PLEASE!!! WILL GIVE BRAINLIEST!!!

Mathematics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

-0.4

Step-by-step explanation:

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HELP ANYONE BRAINLIEST
k0ka [10]

Answer:

12 cups of mild

Step-by-step explanation:

3x3 is 9 and 3/4x9 is 12/4 so 3 9+3 is 12

7 0
3 years ago
Read 2 more answers
1. At a basketball championship game, students were polled and 82% of the students said that basketball is better than football.
zhuklara [117]

Step-by-step explanation:

(A)It says AT A BASKETBALL CHAMPIONSHIP so obviously most people there would’ve said basketball.

(B) Maybe try doing the whole school and not just the students at the basketball championship.

hope this helped! if you need anything else let me know. <3

8 0
4 years ago
If Zach has 4 times as many dimes as quarters and they have a combined value of 455 cents, how many of each coins does he have?
aliya0001 [1]

<u>ANSWER: </u>

Zach has 28 dimes and 7 quarters.

<u>SOLUTION: </u>

Given, Zach has 4 times as many dimes as quarters  

And they have a combined value of 455 cents,  

We need to find how many of each coins does he have?

Let, the number of dimes be x and number of quarters be y.

Then, x = 4y → (1)

Total combined value = 455 cents

x(value of one dime) + y(value of one quarter) = 455 cents

x(10 cents) + x(25 cents) = 455 cents

10x + 25y = 455 → (2)

Now, substitute (1) in (2)

10(4y) + 25y = 455

40x + 25y = 455

65y = 455

y = 7

substitute y value in (1)

x = 4(7)  = 28

Hence, zach has 28 dimes and 7 quarters.

4 0
3 years ago
What is the probability you roll doubles on two 6 sides dice <br> please show work
Mars2501 [29]

Answer:

1/6

Step-by-step explanation:

We can start by determining all the different combinations we can get.

We are using 6 sided dices, so we have a chance of getting 6 different numbers for each dice.

If we only have 1 dice, the our possible values would be:

1, 2, 3, 4, 5, 6

However, we have 2 dices. As such, our combinations have been multiplied, and now our possibilities are:

(1 , 1) , (1 , 2) , (1 , 3) , (1 , 4) , (1 , 5) , (1 , 6) , (2 , 1) , (2 , 2) , (2 , 3) , (2 , 4) , (2 , 5) , (2 ,6), and so on for 3, 4, 5, and 6

We can find the number of combinations by simply multiplying the amount of possible values for each dice.

Since both dices have 6 possible values, we multiply 6 by 6, and the amount of possible combinations is 36.

Now, let's determine the possibility for getting a double.

First, let's determine how many doubles we can get:

(1 , 1) , (2 , 2) , (3 , 3) , (4 , 4) , (5 , 5) , (6 ,6)

There are 6 different combinations for rolling a double.

So, our probability of rolling a double on two 6 sided dices is 6 out of 36

We can simplify that to 1 out of 6.

So the probability of rolling a double on two 6 sided dices is 1/6

8 0
3 years ago
There are 12 teams in the Jayhook Hockey League. Each team plays every other team twice per season, once at home and once away f
zvonat [6]

Answer:

Each team played 22 games.

Step-by-step explanation:

There are 12 teams in the league, so each team has 11 rival teams. Since each team will play against a rival team twice, that means that each team will need to play 11 x 2 = 22 games per season. Of these 22 games, 11 games will be played at home while 11 games will be played away from home.

We can calculate this by using the following formula:

Total number of games played by each team = (n - 1) x 2, where n is the total number of teams in a league.

3 0
3 years ago
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