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guajiro [1.7K]
2 years ago
5

Find all zeros of x^4+x

Mathematics
1 answer:
Yuri [45]2 years ago
4 0

Answer:

-1 and 0

Step-by-step explanation:

X ^4+x = 0;

x*(x^3+1)=0;

x*[(x^3-x)+(x+1)]=0;

x*[x(x-1)(x+1)+(x+1)]=0;

x*(x+1)(x^2-x+1)=0;

Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0

x=0 or -1

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Hey could anyone explain how to answer this kind of question? Or just solve and show what you did! Thank you!
STALIN [3.7K]

Step-by-step explanation:

  • 9x-3=60°{each angle of equilateral triangle is 60°}
  • 9x=60+3
  • x=63/9
  • x=7

so,

  • 9x-3
  • 9×7-3
  • 63-3
  • 60°

hope it helps.

4 0
3 years ago
Need help!
Maslowich
Answer: Choice D) |K| = 57

------------------------------------------------------

Explanation:

The notation |K| means "the number of items in set K". It is similar to the notation n(K). In this case, we simply add up all the values in the circle labeled K. There are four of these values which are 13, 8, 17, 19. Add up these values to get 13+8+17+19 = 57. So there are 57 items in set K.
4 0
3 years ago
You move down 6 units and left 9 units. You end at (-5, -3). Where did you start?
Olegator [25]
(4, 3) i think lol goodluck
6 0
3 years ago
7w+5=3w-15 what is the answer
dem82 [27]
<span>7w+5=3w-15

7w-3w=-15-5

4w=-20

w=-5</span>
4 0
3 years ago
Simplify the trigonometric expression.
Natasha_Volkova [10]
First we are going to find the common denominator of both fractions. To do that, we are going to multiply their denominators:
(1+sin \alpha )(1-sin \alpha )=1-sin^2 \alpha

Now we can rewrite our expression using the common denominator:
\frac{1-sin \alpha }{1-sin^2 \alpha } + \frac{1+sin \alpha }{1-sin^2 \alpha} = \frac{2}{1-sin^2 \alpha}

Finally, we can use the trig identities: 1-sin^2 \alpha =cos^2 \alpha and sec \alpha = \frac{1}{cos \alpha } to simplify our trig expression:
\frac{2}{cos^2\alpha}=2sec^2 \alpha

We can conclude that the correct answer is the fourth one.
5 0
3 years ago
Read 2 more answers
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