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3 years ago

HELP ME PLEASE IT IS A QUICK PROBLEM AND I HAVE 4 MINUTES LEFT!!

Mathematics

1 answer:

GaryK [48]3 years ago

7 0

Answer:

Uuh whats the problem

Step-by-step explanation:

Mark as brainliest

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Write a proportion to find how many points x a student needs to score on a test worth 50 points to get a test score of 40%. $$On

lesya [120]

2 ways to describe the proportion of 40% out of 50 points are:

20/50
or
2:5

7 0

4 years ago

Which point is on the graph ofx=13(y−18)in the coordinate plane?

natulia [17]

The points on a graph are the points that lie on the graph

The ordered pair on the graph of $\mathbf{x =\frac{1}{3}(y - \frac 18)}$ would be $\mathbf{( \frac{5}8},2)$

<em>The points are not given; so, I will give a general explanation</em>

The equation is given as:

$\mathbf{x =\frac{1}{3}(y - \frac 18)}$

Assume that the value of y, is 2

The equation becomes

$\mathbf{x = \frac 13(2 - \frac 18)}$

Take LCM

$\mathbf{x = \frac 13(\frac{16-1}8)}$

$\mathbf{x = \frac 13(\frac{15}8)}$

Divide

$\mathbf{x = \frac{5}8}$

So, the ordered pair would be $\mathbf{( \frac{5}8},2)$

Read more about graphs and ordered pairs at:

brainly.com/question/12716270

6 0

3 years ago

I need help on all r questions I answered right

yaroslaw [1]

Show the problems my guy

4 0

4 years ago

Angle α lies in quadrant II , and tan α = <img src="https://tex.z-dn.net/?f=-%5Cfrac%7B12%7D%7B5%7D" id="TexFormula1" title="-\f

Hunter-Best [27]

Since $\alpha$ lies in quadrant II and $\beta$ lies in quadrant IV, we expect $\sin\alpha>0$ , $\cos\alpha$ , and $\sin\beta$ .

Recall the Pythagorean identities,

$\sin^2x+\cos^2x=1\iff1+\cot^2x=\csc^2x\iff\tan^2x+1=\sec^2x$

It follows that

$\sec\alpha=\dfrac1{\cos\alpha}=-\sqrt{\tan^2\alpha+1}=-\dfrac{13}5\implies\cos\alpha=-\dfrac5{13}$

$\sin\alpha=\sqrt{1-\cos^2\alpha}=\dfrac{12}{13}$

$\sin\beta=-\sqrt{1-\cos^2\beta}=-\dfrac45$

Recall the angle sum identity for sine:

$\sin(\alpha+\beta)=\sin\alpha\cos\beta+\sin\beta\cos\alpha$

So we have

$\sin(\alpha+\beta)=\dfrac{12}{13}\dfrac35+\left(-\dfrac45\right)\left(-\dfrac5{13}\right)=\boxed{\dfrac{56}{65}}$

4 0

3 years ago

Mags is 2 years older than Vector.Which equation will help you find Mags' age (m) if you know Vector's age (v)?

saveliy_v [14]

Answer:

Step-by-step explanation:

m = megs age

v = vectors age

meg is 2 years older than vector + 2

therefore

m = v +2

5 0

4 years ago