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kvasek [131]
3 years ago
9

I need help on this math problem.

Mathematics
1 answer:
OLEGan [10]3 years ago
6 0

B: (0, a)

C should have the same y value as B

D: (a,0)

C should have the same x value as D


So point C is (a,a)

Since point A is on the origin, its point is (0,0)


You use the slope formula and plug in point A and C:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{a-0}{a-0}

m=\frac{a}{a}

m = 1


So the value that belongs in the green box is 1


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Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }

Hence, ∛27 = 27^{(\frac{1}{3})}

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}

Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the <u><em>multiplicative inverse</em></u> of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

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3 years ago
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Step-by-step explanation:

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2 years ago
Sutopa has 3/4 of the money Maneet has. Maneet has $18 less than Kim. Together, they have $286.40. How much money does each of t
anastassius [24]

Solving a system of equations we can see:

  • Sutopa has $73.20
  • Maneet has $97.60
  • Kim has $115.60

<h3>How much money each of them has?</h3>

First, let's define the variables:

  • S =  money that Sutopa has.
  • M = money that Maneet has.
  • K = money that Kim has.

We can write the system of equations:

S = (3/4)*M

M = K - $18

S + M + K = $286.40

First, we can rewrite the second equation to get:

K = M + $18

Now we can replace the first and second equations into the third one:

(3/4)*M + M + (M + $18) = $286.40

Now we can solve this for M:

M*(1 + 1 + 3/4) = $286.40 - $18

M = $268.40*(4/11) = $97.60

Now we can find the other two values:

K = M + $18 =  $97.60 + $18 = $115.60

S =  (3/4)*M =  (3/4)*$97.60 = $73.20

If you want to learn more about systems of equations:

brainly.com/question/13729904

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Construct an inscribed circle in triangle PQR by finding the incenter of the triangle.
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Answer:

Step-by-step explanation:

To inscribe a circle in a given triangle PQR means to construct a circle in the triangle PQR. The incenter of a triangle is the midpoint in the triangle, which can be located by bisecting the three angles of the triangle individually.

The construction is shown in the attachment.

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