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SIZIF [17.4K]
3 years ago
5

Andrea deposited 138 dollars into er bank accont.write an expression representing Andrea's bank account.

Mathematics
2 answers:
Otrada [13]3 years ago
4 0

Answer:

x + 138 = y

Step-by-step explanation:

X is the amount that the bank account had before and y is the amount she has in total

marin [14]3 years ago
3 0

Answer:

x + 138 = x + 138

Step-by-step explanation:

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it is 3

Step-by-step explanation:

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5 0
2 years ago
Use each of the digits 2, 3, 7, and 8. Make it two different multiplication problems so that each product is larger than 5000. U
SVEN [57.7K]
83 x 72 = 5,976. 82 x 73 = 5,986. The way to do this is to take the two biggest numbers and use them in the tens place. Then take the other numbers and put them in the ones space. Then switch the ones slot numbers around to get two different numbers over 5000.
6 0
3 years ago
Algebra about ages please help
valentinak56 [21]

To solve this problem, we need to recognize that Harry's age is given as "n".  We can use this value and the given information to write expressions representing each person's age.

For Example, Jo is 2 years older than Harry and Harry's age is represented by the variable n.  This means that n (Harry's age) plus 2 would equal Jo's age.  This can be represented by the expression: n +2.

Next, we know that Kate is twice as old as Jo, and Jo's age is represented by the expression n+2.  This means that 2 times Jo's age would be equal to Kate's age, or Kate's age = 2(n+2) or 2n +4.

Therefore, your answer is that Jo's age is n + 2 and Kate's age is 2n + 4.

Hope this helps!

3 0
3 years ago
Find all the values of x where the tangent line is horizontal.<br> 2x^3+36x^2+192x+12
Afina-wow [57]
At x = -4 and -8
Take the derivative of the given equation to find rate of change of the graph.
f'(x) = 6x^2 + 72x + 192
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3 0
3 years ago
If 3/4 of a ton of sand covers 2/5 of a playground, how many tons of sand are required to cover the entire playground?
saw5 [17]
3t/4=2p/5  solve for p

p=15t/8

p=1.875 tons of sand
5 0
3 years ago
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