Combinatorial Enumeration. That whole class was a rollercoaster ride of mind-blowing generating functions to prove crazy things. The exam had ridiculous questions like 'count the number of cactus trees with n vertices such that etc etc etc' and you'd do three pages of terrible terrible sums and algebra. Then your final answer would be something beautiful like n/2 and you'd breath a sigh of relief and thank the math gods.
Honestly i just wanted to try this question since ive never seen it but i dont rlly know if i did it right at all
I equaled GH, HI, and GI together to get y
which i got y=-2
and what i got next i feel is off since
GH, HI, and GI all equaled -11
if you kind of know how to do the question maube you could correct me from there but otherwise dont take my word for it completely
Answer:C=2πr=2·π·2≈12.56637in
Step-by-step explanation:
Answer:
The probability that exactly 19 of them are strikes is 0.1504
Step-by-step explanation:
The binomial probability parameters given are;
The probability that the pitcher throwing a strike, p = 0.675
The probability that the pitcher throwing a ball. q = 0.325
The binomial probability is given as follows;
Where:
x = Required probability
Therefore, the probability that the pitcher throws 19 strikes out of 29 pitches is found as follows;
The probability that exactly 19 of them are strikes is given as follows;
Hence the probability that exactly 19 of them are strikes = 0.1504
It took him 1 hour and 13 minutes to go from changuanas to port-of-spain
