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3 years ago

4. Which of the following is NOT one of the three ways to express a ratio? a. b. 3:4 c. 3 of 4 d. 3 to 4 5.

Mathematics

2 answers:

Sergio039 [100]3 years ago

6 0

Answer:

i believe it is C- 3 of 4

kondor19780726 [428]3 years ago

4 0

Answer:

The answer will be c. 3 of 4

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I'm doing elimination in systems of equations how do I solve this?????? Help!!!

Eddi Din [679]

X-3y=-5
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3 years ago

How can you get 24 by using 1, 1/2, 3 and 6 (one each) with simple mathematical operations?

Tcecarenko [31]

Answer:

(3+1)X 6

Step-by-step explanation:

that means 4x6

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3 years ago

Two gardens are being fenced in. Both gardens will require the same amount of fencing (both gardens have the same perimeter in m

Naily [24]

Answer: We know:

the triangle gardern(garden A) and the square garden(garden B) have the same perimeter.

This may sound obv, but it's important: garden A has 1 less side then garden B, which is why it can have longer sides but the same perimeter.

So side A1 + side A2 + side A3 = side B1 + side B2 + side B3 + side B4.

A1 + A2 + A3 = B1 + B2 + B3 + 15(the extra length on the triangle sides)

Since B is a square, B = 15 m by 15 m.

I don't know enough about triangle to put the dementions, but it's an equilateral triangle so the sides are 20 m each. Hope that helps! :)

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2 years ago

Expand the following <br> (x+3)(x+2)

Lisa [10]

Step-by-step explanation:

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3 years ago

Determine the function which corresponds to the given graph. (3 points)

damaskus [11]

Answer:

The center of the circle is c=50 and radius of the circle is $r=\sqrt{3}$

Step-by-step explanation:

Given circle equation is

$x^2-4x+y^2+14y=-50\hfill(1)$

Equation (1) can be written as $x^2-4x+y^2+14y+50=0\hfill(2)$

we know that the equation of the circle is of the form

$x^2+y^2+2gx+2fy+c=0\hfill(3)$

with centre (-g,-f) and radius= $\sqrt{g^2+f^2-c}$

when, g,f and c are constants

Now comparing the (2) and (3) equations we get 2g=-4

$g=\frac{-4}{2}$

$g=-2$

$2fy=14$

$f=\frac{14}{2}$

$f=7$

and $c=50$

Now to find the centre and radius of the given circle equation, substituting the values of g,f,c in the formulae of centre and radius

centre=(-g,-f)

=(-(-2),-7)

centre=(2,7)

Radius= $\sqrt{g^2+f^2-c}$

= $\sqrt{(-2)^2+(7)^2-50}$

= $\sqrt{4+49-50}$

= $53-50$

Radius= $\srqt{3}$

The center of the circle is c=50 and the radius of the circle equation $r=\sqrt{3}$

6 0

3 years ago