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Gwar [14]
3 years ago
5

Round 0.817446 to the ten-thousandths place.

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

0.8174

Step-by-step explanation:

You just round up to the 4th to the right

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What is the area of the regular octagon with a side length of 10 m and an apothem of 12.1 m?
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A = 2 * a^2 * (1 + sqrt 2)

Where 'a' is the side length.

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Therefore, the closest one is C.
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Andy borrows $3890 over 4 years. What was the rate per annum of the loan if he paid back $5908?
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Answer:

The formula to get the rate R would be:

principal x (1+R)^time = (principle + interest)

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Hope this helps!

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3 years ago
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marusya05 [52]
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4 years ago
Unit 8: Right Triangles &amp; Trigonometry<br> Homework 2: Special Right Triangles
Vsevolod [243]

Answer:

Part 1) x=14\sqrt{2}\ units

Part 2) y=14\ units

Part 3) z=14\sqrt{3}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ABC

we know that

The triangle ABC is a 45^o-90^o-45^o

so

Is an isosceles right triangle

The legs are equal

therefore

AC=AB

x=14\sqrt{2}\ units

step 2

Find the length side BC

Applying the Pythagorean Theorem]

BC^2=AB^2+AC^2

BC^2=(14\sqrt{2})^2+(14\sqrt{2})^2

BC^2=784\\BC=28\ units

step 3

Find the value of y

In the right triangle BCD

sin(30^o)=\frac{BD}{BC} ----> by SOH (opposite side divided by the hypotenuse)

sin(30^o)=\frac{y}{28}

Remember that

sin(30^o)=\frac{1}{2}

so

\frac{y}{28}=\frac{1}{2}\\\\y=14\ units

step 4

Find the value of z

In the right triangle BCD

cos(30^o)=\frac{DC}{BC} ----> by CAH (adjacent side divided by the hypotenuse)

cos(30^o)=\frac{z}{28}

Remember that

cos(30^o)=\frac{\sqrt{3}}{2}

so

\frac{z}{28}=\frac{\sqrt{3}}{2}\\z=14\sqrt{3}\ units

3 0
3 years ago
Read 2 more answers
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