Question

Please answer this question​

Answer 1

Answer:

Step-by-step explanation:

2)f(x) = 2x² +4x - 3    

a = 2 ; b = 4 ; c = -3

1) Put x = -1 in the equation

f(x) = 2*(-1)² + 4*(-1) -3 = 2 - 4 -3 = -5

Vertex = (-1,-5)

2) Upward

3) Minimum

4) axis of symmetry = -b/2a = -4/2*2=-4/4= -1

x = -1

5) domain: all real numbers  (-∞ ,∞)

Range : y ≥ -5 ; [-5 , ∞)

3) f(x) = 3x² - 6x + 4

Vertex : (1,1)

Opening : upward

Minimum

Axis of symmetry: x = 1

Domain: all real numbers

Range: y ≥ 1 ; [1, ∞)

4)f(x) = -x² - 2x - 3

a) Vertex:  f(x) = -(-1)² - 2*(-1) - 3 = -1 + 2 - 3 = -2

Vertex( -1,-2)

b) downward

c) Maximum

d) Axis of symmetry: x = 2/-2 = -1  

x = -1

e) Domain: all real numbers

Range: y ≤ -2 ; (-∞ , -2]

5)f(x) = 2(x -2)²

a) Vertex: (2, 0)

b) Opening: upward

c) Minimum

d) x = 2

e)Domain: all real numbers

Range: y ≥ 0 ; [0,∞)