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3 years ago

The quotient of 17 and k

Mathematics

1 answer:

myrzilka [38]3 years ago

8 0

The answer is 17/k because there is no exact way to divide so 17/k is the quotient. :)

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the cost of renting a scooter is represented by 3j+5. Write and simplify an expression that represents the cost of renting 6 sco

wariber [46]

Simplified expression that represents the cost of renting 6 scooters is 18 j +30

<u>Step-by-step explanation:</u>

Given data:

The cost of renting of a scooter is represented by 3j +5

So, from that, we can say in general,

The cost of renting of n scooters is represented by

$n \times(3 j+5)$

But according to given, the value of n is 6. i.e. to find the cost for six number of scooters. We can calculate now as follows

So, the cost of renting of a scooter is represented by

$6 \times(3 j+5)=18 j+30$

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3 years ago

4.6w - 3 + 6.4x - 1.9y

torisob [31]

Answer:

What do you want me to do? Its already simplified to its lowest terms

7 0

3 years ago

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Find the projection of u onto v<br> URGENT HELP

padilas [110]

Given:

Two vectors are:

$u=\left$

$v=\left$

To find:

The projection of u onto v.

Solution:

Magnitude of a vector $v=\left$ is:

$|v|=\sqrt{a^2+b^2}$

Dot product of two vector $v_1=\left$ and $v_2=\left$ is:

$v_1\cdot v_2=a_1a_2+b_1b_2$

Formula for projection of u onto v is:

$Proj_vu=\dfrac{u\cdot v}{|v|^2}v$

$Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left$

$Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left$

$Proj_vu=\dfrac{0+102}{293}\left$

On further simplification, we get

$Proj_vu=\dfrac{102}{293}\left$

$Proj_vu=\left$

Therefore, the projection of u onto v is $Proj_vu=\left$ .

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3 years ago

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Lyrx [107]

3.2E-9

A bit complicated, so PLEASE don't ask for an explanation

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4 years ago

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blagie [28]

Richard had to pay 0.87

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