Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
Answer:
Step-by-step explanation:
We are given the following information in the question.
The open interval: (- 18,22).
Let p belong to the given interval then p represents all the values belonging to the given interval.
Open Interval: An open interval is a interval that does not include the end points.
Thus, we can write:
is the required inequality form required.
That is p can take values greater than -18 and smaller than 22.
Don’t know if there’s much of an equation for it, but I guess the best way to write it out is 10 + x = -18. Then, you would subtract the 10 from both sides in order to isolate the x. So then you’re left with x = -28. So -28 is your answer.
His sister is 7.895 feet tall.
Answer:
1/12 lb
Step-by-step explanation:
2/3 x 1/8 = 2/24 = 1/12
