Answer:
6 units
Step-by-step explanation:
Answer:
Check the ecplanation
Step-by-step explanation:
A set of three vectors in 
represents a matrix of 3 column vectors, and each vector containing 4 entries (that is, a matrix of 4 rows, and 3 columns).
Let A be that 4x 3 matrix. The columns of A span 
. if and only if A has a pivot position in each row. So, there are at most 3 pivot positions in the matrix A, but the number of rows is 4, therefore, there exist at least one row not having a pivot position. If A does not have a pivot position in at least one row, then the columns of A do not span . It implies that the set of 3 vectors of A does not span all of .
In general, the set of n vectors in represents a matrix of in rows, and n columns (an in x matrix). So, there are at most n pivot positions in the matrix A, but n is less than the number of rows. In therefore, there exist at least one row that does not contain a pivot position.
And, hence the set of n vectors of A does not span all of . for n < m
Answer:
I think it would be 3y+3y-12 because 6y=3y+3y
Step-by-step explanation:
The answer to your question is 34.13%
