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2 years ago

Can somebody please help me

Mathematics

1 answer:

Nataly [62]2 years ago

5 0

Answer:

The probability of drawing the first pink ball is $\frac{3}{10}$ .

Because you drew that first pink ball, there are two pink balls left and the total number of balls left is nine.

Hence, the probability of drawing another pink ball after drawing the first pink ball would be:

$\frac{3}{10} *\frac{2}{9} =\frac{1}{15}$

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What is the most precise name for a quadrilateral with the following vertices:

pashok25 [27]

<h2>Therefore it is a parallelogram.</h2>

Step-by-step explanation:

Given the vertices of the quadrilateral are A(2,3) , B(7,2), C(6,-1) and D(1,0)

The length of AB is $=\sqrt{(2-7)^2+(3-2)^2}$ $=\sqrt{26}$ units

The length of BC is $=\sqrt{(7-6)^2+(2+1)^2}$ $=\sqrt{10}$ units

The length of CD is $=\sqrt{(6-1)^2+(-1-0)^2}$ $=\sqrt{26}$ units

The length of DA is $=\sqrt{(1-2)^2+(0-3)^2}$ $=\sqrt{10}$ units

The length of AC is $=\sqrt{(2-6)^2+(3+1)^2}$ $=4\sqrt{2}$ units

The length of BD is $=\sqrt{(7-1)^2+(2-0)^2}$ = $2\sqrt{10}$ units

Here length of AB = length of CD ,

length of BC= length of DA and

length of AC ≠ length of BD

In this quadrilateral, the opposite sides are equal but the diagonals are not equal

Therefore it is a parallelogram.

3 0

3 years ago

Rectangle A is a scale drawing of Rectangle B and has 25% of its area. If rectangle A has side lengths of 4 cm and 5 cm , what a

SpyIntel [72]

Answer:

8 cm and 10 cm

Step-by-step explanation:

Hello, <em> </em>I can help you with this.

Step 1

According to the question there are two rectangles A and B,

Rectangle A is a scale drawing of Rectangle B and has 25% of its area

in other words

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\$

Step 2

Let

Rectangle A

length (1)= 4 cm

length (2)= 5 cm

$Area_{A}=4\ cm * 5\ cm\\Area_{A}=20\ cm^{2}$

put this value into equation 1

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\\\20\ cm^{2} =0.25*Area_{B} \\divide\ each\ side\ by\ 0.25\\\frac{20\ cm^{2} }{0.25}=\frac{0.25}{0.25}*Area_{B}\\ Area_{B}=80\ cm^{2}$

Now, we know the area of rectangle B, to know its length we need to formule other equation

Step 3

$Area_{B}=80\ cm^{2}\\length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\$

the ratio between the lengths must be constant, so the ratio of A must be equal to ratio in B, then

$\frac{length(1A)}{length(2A)}=\frac{length(1B)}{length(2B)} \\\\\\frac{4}{5}= \frac{length(1B)}{length(2B)}\\0.8=\frac{length(1B)}{length(2B)}\\length(1B)=0.8*length(2B) (Equation 3)$

Step three

using Eq 1 and Eq 2 find the lengths

put the value of length(1B) into equation (2)

$length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\\(0.8*length(2B)) (*length (2B)=80\ cm^{2} \\\\0.8*(length (2B))^{2} =80\ cm^{2}\\(length (2B))^{2} =\frac{80\ cm^{2}}{0.8} \\(length (2B))^{2}=100\\\sqrt{(length (2B))^{2}}=\sqrt{100\ cm^{2}} \\ length (2B)=10\ cm$

Now, put the value of length(2B) into equation 3 to know length (1B)

$length(1B)=0.8*length(2B)\\length(1B)=0.8*10\ cm\\length(1B)=8 cm$

I really hope this helps you, have a great day.

6 0

3 years ago

Change 84cm into millimetres

Mars2501 [29]

Answer:

840 mm

Step-by-step explanation:

multiply by 10

7 0

2 years ago

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The ratio of dark chocolate candies to white chocolate candies is 3 to 2. There are 18 pieces of dark chocolate. How many pieces

ch4aika [34]

there are 18 pieces of dark chocolate and the ratio of dark and white is 3:2 so we can divide 18 by 3.

18/3 = 6.

This means the ratio of dark chocolate to white as a 1:1 ratio would be 6:6 so we can multiply 6 by 2 to give us the total amount of pieces of white chocolate.

6*2 = 12.

Therefore there are 12 white chocolate pieces.

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3 years ago

Find the common difference of the arithmetic<br> sequence 4, 10, 16,

DIA [1.3K]

Answer:

10it is 10

Step-by-step explanation:

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2 years ago

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