Design a chip that can complete four bit binary addition, subtraction, and, or operation. Complete the Verilog program and show
2 answers:
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Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.
Answer:
The program to this question can be described as follows:
Program:
#include <iostream> //defining header file
using namespace std;
int main() //defining main method
{
int x; //defining integer variable
for(x=0;x<=100;x++) //defining loop to count value from 0 to 100
{
if(x%7==0) //check value is divisable by 7
{
cout<<x<<endl; //print value
}
}
return 0;
}
Output:
please find the attachment.
Explanation:
In the above code, an integer variable x is declared, which is used in the for loop, in this loop variable "x" starts from 0 and ends when the value of x is less than and equal to 100.
- Inside the loop an, if block is used that defines a condition that is (i%7==0), it will check, that the value is divided by 7.
- In this loop, a print method is used, that prints its values.
