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Zinaida [17]
2 years ago
10

Given the formula:

" title="x = \frac{1 + a}{1 - a} " alt="x = \frac{1 + a}{1 - a} " align="absmiddle" class="latex-formula">
Solve for "a" when x=12.​
Mathematics
1 answer:
shtirl [24]2 years ago
8 0

12 = \frac{1+a}{1-a} => 12(1-a)= 1+ a \\=> 12 -12a = 1 + a => 12a+1 = 12-1 \\=> 13a = 11 => a= \frac{11}{13}

ok done. Thank to me :>

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kolbaska11 [484]
I think it’s A sorry if I’m wrong:)
8 0
3 years ago
Let f(x) = twenty-four over the quantity of 3 x minus two. Find f(-2
bija089 [108]
f(x)=\frac{24}{3x-2}\\\\f(-2)=?\\
Subtitude\ x=-2\\
f(-2)=\frac{24}{3*(-2)-2}=\frac{24}{-6-2}=\frac{24}{-8}=-3\\\\
Solution\ is\ f(-2)=-3.
4 0
3 years ago
Read 2 more answers
Two arithmetic means between 3 and 24 are -
defon

The value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.

<h3>What is arithmetic mean?</h3>

Arithmetic mean is the mean or average which is equal to the ratio of sum of all the group numbers to the total numbers.  

The two arithmetic means between 3 and 24 are has to be inserted.

3, A₂, A₃, 24

All the four numbers are in arithmetic progression. The nth terms of AM can be found using the following formula:

t(n)=a(n-1)d

Here, d is the common difference a is the first terms and n is the total term.  The first term, a=3 and t₄=24. Thus, the common difference is;

t(n)=a(n-1)d\\t(4)=3(4-1)d\\24=3(3)d\\24=9d\\d=\dfrac{24}{9}

The second and 3rd term are:

A₂=3+\dfrac{24}{9}=\dfrac{51}{9}\\ A₃=\dfrac{51}{9}+\dfrac{24}{9}=\dfrac{75}{9}

Thus, the value of two arithmetic means which are inserted between 3 and 24 are 24/9 and 75/9.

Learn more about the arithmetic mean here;

brainly.com/question/14831274

#SPJ1

8 0
2 years ago
What is the perimeter of a polygon with vertices at (−2, 1) , ​ (−2, 4) ​, (2, 7) , ​ (6, 4) ​, and (6, 1) ​?
alekssr [168]
First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
d =  \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }
d1 =  \sqrt{{(1 - 4)}^{2} + {( - 2 -  - 2)}^{2} } \\  =  \sqrt{{(- 3)}^{2} + {(0)}^{2} } =  \sqrt{9}  \: = 3
d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\  = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } =  \sqrt{9 + 16}  \\  =  \sqrt{25}  \: = 5
d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\  =  \sqrt{{(3)}^{2} +  {( - 4)}^{2} } =  \sqrt{9 + 16}  \\  =  \sqrt{25} \:  = 5
d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\  =  \sqrt{ {(3)}^{2} +  {(0)}^{2}  }  =  \sqrt{9} \:  = 3
d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} }  \\ =  \sqrt{ {(0)}^{2} +  {( - 4)}^{2}} =  \sqrt{16}  \:  = 4
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units





5 0
3 years ago
Read 2 more answers
Help I will be marking brainliest!!!
Andrews [41]
The answer is b

work is attached as a pic, in future draw a diagram, it’ll help u understand

3 0
3 years ago
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