ABC = 408
C + 7 = B
A + 5 = B
B - 7 + B - 5 + B = 408
3B - 12 = 408
+ 12 = +12
3B = 420
/3 = /3
B = 120
A = 115
C = 113
The answer is A = 115, Abel has $ 115
Answer:
1/2.25 or 4/9
Step-by-step explanation:
Given:
The equation is:

To find:
The graph of the line that contains ordered pairs that are solutions of the given equation.
Solution:
We need to find the graph of the given equation.
We have,

At
, we get


So, the x-intercept of the given equation is at point (0,4).
At
, we get


So, the y-intercept of the given equation is at point (4,0).
From the given graphs it is clear that the line in option C has x-intercept at point (0,4) and y-intercept at point (4,0).
Therefore, the correct option is C.
Answer:
x=y=z=90.
Step-by-step explanation:
let the 3 numbers be x,y,z.
let s be sum
s=x+y+z
we need to maximize xy+yz+zx
or , xy + y(270-(x+y))+x(270-(x+y)) = P(x)
Use Lagrange's Multipliers
⇒ΔP= λΔS
⇒
⇒y=x
⇒\frac{x+z}{x+y} =1
⇒z=y
⇒x=y=z
⇒3x = 270
⇒x= 90
hence, x=y=z=90.
Answer:
x is to the side y is up so you´d put A on 4 side 9 up
Step-by-step explanation: